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ivolga24 [154]
3 years ago
10

Find FD(round to the nearest tenth) please and thank you!

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

FD = 25.9

Step-by-step explanation:

13x - 16 = 4x + 11

9x = 27

x = 3

using Pythagorean theorem:

FD²  = 12² + [4(3) + 11]²

FD² = 144 + 23² = 144 + 529 = 673

FD = 25.94

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What are the y-coordinates for the solution to the system of equations:{y−x2+9x−6=0
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Answer:

c

Step-by-step explanation:

7 0
3 years ago
The image of the polygon ABCDE reflected across the x-axis. A(-1,-1),B(0,1),C(4,2),D(6,0),E(3,-3) The vertices of the image are.
4vir4ik [10]

A reflection across the x-axis has the rule:

(x,y)→(x,-y).

Then:

  • A(-1,-1)→A'(-1,1),
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6 0
3 years ago
Find the measure of the segment indicated.
julsineya [31]
Answer is QM = 18

You can find the length of QM by using Pythagorean theorem. See the attachment.

It is a quadrilateral with 4 equal congruent sides.

If SP = 30, so do the other 3 sides indicated by the tick marks on all 4 sides.

We will call side RQ = the hypotenuse
or side “c” = 30
We know RM is leg “b” = 24
Side “a” is our unknown QM

Our formula is
a^2 + b^2 = c^2

a^2 + 24^2 = 30^2

a^2 + 576 = 900

a^2 = 900 - 576

a^2 = 324

Take square root of both sides to solve a

a = 18

QM = 18

3 0
1 year ago
1.62 rounded to the nearest tenth
hjlf
The answer to this equation is 1.6
7 0
3 years ago
Read 2 more answers
A group of college students built a self-guided rover and tested it on a plane surface. They programmed the vehicle to move alon
makkiz [27]

Answer:

B. 40 meters

Step-by-step explanation:

— Estimating

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The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.

Only one answer choice fits in the range 37 < d < 46.

____

— Detailed calculation

The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.

The circuit length is ...

AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters

4 0
3 years ago
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