Area of pool edge = Area of big rectangle - Area of the pool
Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.
We also need the width of the big rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10
We can only use the positive value of x since the context is length
Hence, x = 60
Answer:
55 pages per hour
Step-by-step explanation:
You divide 165 by 3 = 55
Answer:
72°
Step-by-step explanation:
You correctly found x, but the measure of the angle is ...
4x-22 = 4·23.5-22 = 72°
___
or (6x-69)° = (141-69)° = 72°
Angles formed by the segment
in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.
- The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; <u>16 over 12 equals 12 over 9</u>
Reasons:
The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;
Segment
is perpendicular to segment 
∠WZX and ∠XZY are right angles by definition of
perpendicular to 
∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)


Therefore;
, which gives, 
Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and
that the included angles between the two sides, ∠WZX and ∠XZY are
congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-
Side, SAS, similarity postulate.
The option that best completes the proof is therefore;
which is; <u>16 over 12 equals 12 over 9</u>
Learn more about the SAS similarity postulate here:
brainly.com/question/11923416
Answer:
Step-by-step explanation:
is pretty simple
292,000/100=2,920