Given , assume a second solution of the form , with derivatives
With , you have and .
Substitute these into the ODE and you get
Now substitute , so that and you have a linear first-order ODE:
But is already accounted for, so the second fundamental solution to the ODE is .
Theorem: If a tangent and a secant meet at an external point, then the product of the length of the secant and its external segment is equal to the square length of the tangent.
If we put this into practice in this question, then it becomes:
x² = 7(21 + 7)
x² = 7 · 28
x² = 196
x = 14, because x > 0
Thus, the length of x is 14 (D)
Answer:
B
this answer for this question
Answer:
What type of recipe is this?
Answer:
Step-by-step explanation:
= x²(-3 +5) +y²(2 -3) +5xy -2y
= 2x² -y² +5xy -2y
a) there are 4 terms in the simplified expression
b) 2 terms have negative coefficients (-y² and -2y)