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Marina CMI [18]
3 years ago
11

Demarco paid $3.19$3.19 per gallon both times that he stopped for gas on a weekend trip. He bought 12.5312.53 gallons of gas the

first time and 11.8611.86 gallons the second time. Which expression shows the total cost in dollars of the gas he bought on this trip?
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0

Answer: The total cost in dollars of the gas is $77.80.

Step-by-step explanation:

since we have given that

Amount of gallon of gas he bought for the first time = 12.53

Amount of gallon of gas he bought for the second time = 11.86

According to question, He paid $3.19 per gallon both the times that he stopped for gas on a weekend trip.

So, our expression that shows the total cost in dollars of the gas he bought on this trip is given by

12.53\times 3.19+11.86\times 3.19\\\\\text{ using distributive law}\\\\=3.19(12.53+11.86)\\\\=\$77.80

Hence, the total cost in dollars of the gas is $77.80.


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The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Pls help and show your work
Dmitriy789 [7]

Answer:

21. Vol. = L ^ 3

or, 27000 = L ^ 3

or, cube root undefr 27000 = L

Therefore, Edge length = 30 cm

22.

a. v = l ^ 3

or, 64000 = l ^ 3

or, cube root under 64000 = L

or, l = 40 cm

Also,

surface area = 6 a ^ 2

= 6 * 40 ^ 2

= 6 * 1600

= 9600 cm ^ 2 #

Hope this helped

Hope this helped ALL THE BEST !!

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matrenka [14]

Answer:

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A ​17-foot ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground feet
artcher [175]

Answer:

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Let’s say you did not know that this was a standard 8–15–17 right triangle.

This is how you can figure it out:

hypotenuse(h)22 = side2112 + side2222

Let side11 = base and side22 = wall

1722 = 822 + wall22

wall = 172−82−−−−−−−√172−82

wall = 289−64−−−−−−−√289−64

wall = 225−−−√225

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Answer:

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