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UkoKoshka [18]
4 years ago
7

The element Aluminium (AI) Is

Chemistry
1 answer:
k0ka [10]4 years ago
4 0

Answer:

a metal which is found in 13 group and 3 period of periodic table

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What is the answer please tell me
Nastasia [14]

Answer:

you need to include the bottom portion, not enough info

Explanation:

5 0
3 years ago
PLZ HELP
Cerrena [4.2K]

Answer:

Your answer will be 118 cm^3.

Explanation:

V1/T1 = V2/T2, so V2 = V1T2/T1. 60C = 333K and 120C = 393K.

V2 = (100cm3)(393K)/(333K) = 118 cm3

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3 years ago
Apart from boiling point and flammability, what other quality does the size of the molecules in hydrocarbons affect?​
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Viscosity

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6 0
3 years ago
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Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an
ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

TiCl_{4(l)} ⇒ TiCl_{4(g)}

ΔH°_{f} (TiCl_{4(l)}) = -804.2 kJ/mol

ΔH°_{f} (TiCl_{4(g)}) = -763.2 kJ/mol

Therefore,

ΔH°_{f} = ΔH°_{f} (TiCl_{4(g)}) - ΔH°_{f} (TiCl_{4(l)}) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(TiCl_{4(l)}) = 221.9 J/(mol*K)

s°(TiCl_{4(g)}) = 354.9 J/(mol*K)

Therefore,

s° = s° (TiCl_{4(g)}) - s°(TiCl_{4(l)}) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH°_{f} /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

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3 years ago
Which of the following best describes repulsions?
poizon [28]
A. to push each other away
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3 years ago
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