Answer: 6.022 x10^23 atoms
Explanation:
Answer: mass and relative abundance of each isotope of that element
Explanation:-
For example:
If an element X has two isotopes with following masses ad abundance:
Mass of isotope 1 = 267.8 amu
% abundance of isotope 1 = 87.8% = 0.878
Mass of isotope 2 = 269.9 amu
% abundance of isotope 2 = 12.2% = 0.122
Formula used for average atomic mass of an element :
Answer:
50 mL
Explanation:
In case of titration , the following formula is used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.50M
V₁ = 100 mL
M₂ = 1.0M
V₂ = ?
Using the above formula , the volume of base , can be calculated as ,
M₁V₁ = M₂V₂
substituting the respective values ,
0.50M * 100 mL = 1.0M * V₂
V₂ = 50 mL
100. g CCl4* (1 mol CCl4/ 153.8 g CCl4)* (6.02*10^23 CCl4 molecules/ 1 mol CCl4)= 3.91*10^23 CCl4 molecules.
(Note that the units cancel out so you get the answer)
Hope this helps~
This is non polar because the elements are relatively close on the periodic table