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alukav5142 [94]
3 years ago
12

PLZ HELP

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

Your answer will be 118 cm^3.

Explanation:

V1/T1 = V2/T2, so V2 = V1T2/T1. 60C = 333K and 120C = 393K.

V2 = (100cm3)(393K)/(333K) = 118 cm3

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Answer: Ions are an atom or molecule with a net electric charge due to the loss or gain of one or more electrons. They are formed when atoms lose or gain electrons in order to fulfill the octet rule and have full outer valence electron shells.

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Gold cylinder has a mass of 75 g and a specific heat of 0.129J/G degrees Celsius it is heated to 65°C and then put in 500 g of w
nadezda [96]
<h3>Answer:</h3>

89.88° C

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of gold cylinder as 75 g
  • specific heat of gold is 0.129 J/g°C
  • Initial temperature of gold cylinder is 65°C
  • Mass of water is 500 g
  • Initial temperature of water is 90 °C

We are required to calculate the final temperature;

  • We know that Quantity of heat is given by the product of mass, specific heat capacity and change in temperature.
  • That is, Q = m × c × ΔT
<h3>Step 1: Calculate the quantity of heat absorbed by the Gold cylinder</h3>

Assuming the final temperature is X° C

Then; ΔT = (X-65)°C

Therefore;

Q = 75 g × 0.129 J/g°C × (X-65)°C

   = 9.675X - 628.875 Joules

<h3>Step 2: Calculate the quantity of heat released by water</h3>

Taking the final temperature as X° C

Change in temperature, ΔT = (90 - X)° C

Specific heat capacity of water is 4.184 J/g°C

Therefore;

Q = 500 g × 4.184 J/g°C × (90 - X)° C

  = 188,280 -2092X joules

<h3>Step 3: Calculate the final temperature, X°C</h3>

we know that the heat gained by gold cylinder is equal to the heat released by water.

9.675X - 628.875 Joules = 188,280 -2092X joules

2101.675 X = 188908.875

              X = 89.88° C

Thus, the final temperature is 89.88° C

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