<u>Answer:</u> The molarity of
ions in the solution is 0.306 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
![\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20the%20solution%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20solute%7D%5Ctimes%201000%7D%7B%5Ctext%7BMolar%20mass%20of%20solute%7D%5Ctimes%20%5Ctext%7BVolume%20of%20solution%20%28in%20mL%29%7D%7D)
We are given:
Mass of solute
= 15.6 g
Molar mass of
= 295.6 g/mol
Volume of solution = 345 mL
Putting values in above equation, we get:
![\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20%7DCu%28NO_3%29_2.6H_2O%3D%5Cfrac%7B15.6g%5Ctimes%201000%7D%7B295.6g%2Fmol%5Ctimes%20345mL%7D%5C%5C%5C%5C%5Ctext%7BMolarity%20of%20%7DCu%28NO_3%29_.6H_2O%3D0.153M)
As, 1 mole of
produces 1 mole of copper (II) ions and 2 moles of nitrate ions.
So, molarity of
ions = (2 × 0.153) = 0.306 M
Hence, the molarity of
ions in the solution is 0.306 M
Answer:
6. solar eclipsis
7. drive less fuel efficient vehicles
Explanation:
these are the only questions i get but i still hope this helps :)
Answer:
From the given variable values, we can calculate the density of the rock sample to be = 10750_Kg/m^3
Explanation:
To solve this question, we recollect that density is the mass per unit volume of a substance and the SI unit of density is Kg/m^3 with symbol
ρ
The given variables are as follows
mass of rock sample = 8.6g
The volume displaced in the graduated cylinder is
(Final volume level of the cylinder) - (initial volume level of the cylinder)
13.6ml - 12.8 ml= 0.8ml = volume of the rock sample
Therefore, density = 8.6/0.8 = 10.75g/ml = or 1000×10.75 Kg/m^3 =10750Kg/m^3
Density of the rock sample is 10750Kg/m^3
The balanced equation for the burning of N-butane is;
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O
stoi. ratio 2 : 13 : 8 : 10
molar mass 58 32 44 18
moles X 13 X/2 8X/2 10X/2
105.86 688.10 423.45 529.31
produced mass 18632.8 g 9527.6 g
moles of n-butane = X = 6.14 x 10³ g / 58 g mol⁻¹
hence other moles of compounds can be calculated.
Mass = molar mass * moles
mass fraction = mass / total mass
hence the mass fraction of
CO₂ = 18632.8 / 6.14 x 10³ = 3.03
H₂O = 9527.6 / 6.14 x 10³ = 1.55
the required mass of air = 688.10 x 32 = 22019.2 g = 2.20 kg
Answer:
10.35%
Explanation:
Find the molar mass of water, using your periodic table: 18.02 g. Then find the molar mass of the total substance: 174.10 g.
Divide the molar mass of water by the molar mass of the total substance and multiply 100%. Doing this, you get 10.35%.