Question

Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your answer to the nearest degree.

Answer 1

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

Ti$Cl_{4(l)}$ ⇒ Ti$Cl_{4(g)}$

ΔH°$_{f}$ (Ti$Cl_{4(l)}$) = -804.2 kJ/mol

ΔH°$_{f}$ (Ti$Cl_{4(g)}$) = -763.2 kJ/mol

Therefore,

ΔH°$_{f}$ = ΔH°$_{f}$ (Ti$Cl_{4(g)}$) - ΔH°$_{f}$ (Ti$Cl_{4(l)}$) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(Ti$Cl_{4(l)}$) = 221.9 J/(mol*K)

s°(Ti$Cl_{4(g)}$) = 354.9 J/(mol*K)

Therefore,

s° = s° (Ti$Cl_{4(g)}$) - s°(Ti$Cl_{4(l)}$) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH°$_{f}$ /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.