Question

When the polynomial 4x^4 − 13x^2 − 2x is divided by the polynomial x − 2 , x-2, what is the remainder?

Answer 1

Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8