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weeeeeb [17]
3 years ago
9

When the polynomial 4x^4 − 13x^2 − 2x is divided by the polynomial x − 2 , x-2, what is the remainder?

Mathematics
1 answer:
zhenek [66]3 years ago
3 0
Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
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Lou wants to make a coffee mixture to sell. He is going to mix Sumatra coffee which costs $2.50 per pound with Columbian coffee
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To answer this question you need to create 2 equations:
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3 years ago
Mustafa’s horse ate 6,400 pounds of hay last year. How could Mustafa determine the number of tons of hay his horse ate last year
Alona [7]

Answer:

by dividing 6,400 by 2,000

Step-by-step explanation:

We know that 2000 pounds  equals 1 ton

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6400 pounds * 1 ton/2000 pounds

Divide 6400 by 2000

3 0
3 years ago
You have 24 months left until you graduate and you plan on buying yourself a new $20,000 car on graduation day. If you invest $3
shusha [124]

Answer: No, the money won't be enough to buy the car

Step-by-step explanation:

you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.

The principal amount, p = 300

He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So

n = 4

The rate at which the principal was compounded is 4%. So

r = 4/100 = 0.04

It was compounded for a total of 24 months. This is equivalent to 2 years. So

n = 2

The formula for compound interest is

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A = total amount that would be compounded at the end of n years.

A = 300(1 + (0.04/4)/4)^4×2

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A = $324.857

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3 0
4 years ago
<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2
guapka [62]

Step-by-step explanation:

\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)

Use the identity

\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}

on the left side.

\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)

Now use the identity

\sin \theta = \cos(\frac{\pi}{2} - \theta)

on the left side.

\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)

4 0
3 years ago
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