Question

An urn contain 2 white marbles, 3 green marbles, and 5 red marbles. A marble is drawn and then replaced. Then a second marble is drawn. What is probability that the first marble was white and the second was green?

Answer 1

Answer:

1/5

Step-by-step explanation:

To find this you would need to multiply the probability of pulling a white marble to the probability of pulling out a green marble.

1)First you would need the probability of pulling out a white marble. There are 10 marbles in total and out of those 2 are white. So the probability of pulling out a white marble would be 2/10. If you simplify that you would get 1/5 for the probability of pulling out a white marble.

2)Next, you would find the probability of pulling out a green marble. Using the same process that we used to find the probability of pulling out a white marble, we would find the answer to be 3/10. All that we did here was green marbles/total marbles. By filling that in we got 3/10 for the probability of pulling out a green marble.

3)Now all that is left is doing probability of pulling a white marble × probability of pulling out a green marble. This would be 1/5 × 3/10. After solving the answer would be 3/15 which we would simplify down to 1/5 as our final answer.