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xxTIMURxx [149]
3 years ago
14

An urn contain 2 white marbles, 3 green marbles, and 5 red marbles. A marble is drawn and then replaced. Then a second marble is

drawn. What is probability that the first marble was white and the second was green?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

<u>Answer:</u>

1/5

<u>Step-by-step explanation:</u>

To find this you would need to multiply the probability of pulling a white marble to the probability of pulling out a green marble.

1)First you would need the probability of pulling out a white marble. There are 10 marbles in total and out of those 2 are white. So the probability of pulling out a white marble would be 2/10. If you simplify that you would get 1/5 for the probability of pulling out a white marble.

2)Next, you would find the probability of pulling out a green marble. Using the same process that we used to find the probability of pulling out a white marble, we would find the answer to be 3/10. All that we did here was <em>green marbles/total marbles</em>. By filling that in we got 3/10 for the probability of pulling out a green marble.

3)Now all that is left is doing <em>probability of pulling a white marble × probability of pulling out a green marble</em>. This would be 1/5 × 3/10. After solving the answer would be 3/15 which we would simplify down to 1/5 as our final answer.

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