I think there are missing details in this question. I'll just discuss what an unenrolled tax preparer is.
Unenrolled Tax Preparers are individuals who <span>possess the minimum qualifications required to prepare federal taxes and are granted a Preparer Tax Identification Number (PTIN) but are not Certified Public Accountants (CPA), lawyers, or enrolled agents.
They are only limited to filing only certain types of tax returns and can only represent their client on the basic audit level before the IRS.
In order for an unenrolled tax preparer to become an enrolled agent, he or she must do the following:
1) Pass a three-part examination before the IRS
2) Undergo compliance check on their tax history
3) Complete 16 hours of continuing education every year to retain their status. </span>
Step-by-step explanation:
<h3>
<em><u>2</u></em><em><u>-</u></em><em><u>3</u></em><em><u>=</u></em><em><u>0</u></em></h3>
<em><u>2</u></em><em><u>2</u></em><em><u>=</u></em><em><u>9</u></em>
<em><u>2</u></em><em><u>-</u></em><em><u>9</u></em><em><u>=</u></em><em><u>0</u></em>
<em><u>2</u></em><em><u>+</u></em><em><u>3</u></em><em><u>2</u></em><em><u>=</u></em><em><u>0</u></em>
Answer:
D
Step-by-step explanation:
We will let d represent the amount of dimes Angela has.
Angel has 5 fewer quarters than twice the number of dimes.
Twice the number of dimes will be 2d.
Then, 5 fewer will yield 2d-5.
Therefore, the amount of quarters Angela has is 2d-5.
Then, the total amount of coins (dimes and quarters) together, will be:
The first part is the amount of dimes.
And the second part is, as we determined, the amount of quarters.
Therefore, our answer is D.
3rd one is correct as it satisfies the eqaution
Answer:
is a factor of
Step-by-step explanation:
is a factor of
We will prove this with the help of principal of mathematical induction.
For n = 1, is a factor , which is true.
Let the given statement be true for n = k that is is a factor of .
Thus, can be written equal to , where y is an integer.
Now, we will prove that the given statement is true for n = k+1
Thus, is divisible by .
Hence, by principle of mathematical induction, the given statement is true for all natural numbers,n.