All categories

2 years ago

Can a right triangle also be obtuse? Explain why or why not.

Mathematics

2 answers:

Alenkinab [10]2 years ago

6 0

Answer:

No, it cannot

Step-by-step explanation:

There are different triangles, right triangle, obtuse, acute are the basic ones and if it was obtuse, it wouldnt be a right triangle

plz mark brainlest!!

vaieri [72.5K]2 years ago

5 0

Answer:

no, because a right angle always has one angle that is 90 degrees. therefore, it cannot open enough, even at 91 degrees, to make it obtuse, or it is not a right triangle.

Step-by-step explanation:

You might be interested in

ABC = EDF. Determine the value of x.

astra-53 [7]

Answer:

The correct answer here is A. x = 17.

How I found this out:

3x + 3 and 5x - 7 are going to be different solutions in the end.

I did the process of elimination.

First, I subsituted, 17 for x. 3 X 17 + 3 = 54. 5 X 17 - 7 = 78.

I then took 180 - 54 - 48 = 78 and 180 - 78 - 48 = 54, just to make sure they are positive numbers and not negative.

Since they work out, I chose this as my correct answer to your question.

Step-by-step explanation:

Hope this helps! :)

I tried my best so I'm it's wrong.

8 0

2 years ago

PLEASE HELP, ILL GIVE YOU 20 POINTS!!!

Troyanec [42]

Answer:

-2,4

Step-by-step explanation:

i think

5 0

3 years ago

Read 2 more answers

One gym costs $24 per month and has a joining fee of $135. Another gym costs $39 per

Evgesh-ka [11]

Answer:

9 months

Step-by-step explanation:

8 0

3 years ago

option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar

motikmotik

Answer:

The equation is given below as

$\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x$

Step 1:

We will work on the left-hand side, we will have

$\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}$

By substituting the identity above, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\ \end{gathered}$

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}$

Here, we will use the definition of subtraction

$\cos x-\frac{\sin^2x}{\cos x}$

Step 3:

We will apply the double number identity given below

$\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}$

By applying this, we will have

$\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}$

Here, we will use the double number identity

$\frac{\cos^2x-\sin^2x}{\cos x}$

5 0

1 year ago

Leonard has 5 times as many stamps as Alison. Melissa has 7 more stamps than Leonard. If Alison has q stamps, how many stamps do

bija089 [108]

The answer is 35 just do 7x5

5 0

2 years ago