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oee [108]
3 years ago
8

To multiply a negative number, you should multiply their absolute values and make the product negative?

Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:

its false

Step-by-step explanation:apex.

Thepotemich [5.8K]3 years ago
3 0
True. because a negative times a positive will equal out to a negative
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I need help it’s homework and idk how to do it
Volgvan

Answer:

  x = 40 1/2

Step-by-step explanation:

The hash marks tell you the triangles are similar and the smaller one is 1/2 the size of the  larger one. Then x is half the length of the corresponding segment marked 81.

  x = 81/2

  x = 40 1/2

___

You may have to write it as 81/2 or as 40.5. Sometimes the answer needs to be in a particular form.

3 0
2 years ago
Please expand the logarithmic expression: Log3(7X^3Y^2)
disa [49]
\log_37x^3y^2=\\\log_37+\log_3x^3+\log_3y^2=\\\log_37+3\log_3x+2\log_3y
8 0
3 years ago
Which of the following is equal to the expression (8x)^-2/3 (27x)¯1/3
LiRa [457]

The equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

<h3>How to evaluate the expression?</h3>

The expression is given as:

(8x)^-2/3 * (27x)^-1/3

Evaluate the exponent 8^-2/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * (27x)^-1/3

Evaluate the exponent (27x)^-1/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * 1/3(x)^-1/3

Multiply 1/4 and 1/3

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^-2/3 * (x)^-1/3

Evaluate the exponent

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-2/3 -1/3)

This gives

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-1)

So, we have

(8x)^-2/3 * (27x)^-1/3 = 1/12x

Hence, the equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

Read more about equivalent expression at

brainly.com/question/2972832

#SPJ1

3 0
10 months ago
Upvote an will mark brainlest
Irina18 [472]

Answer:heyyy there...the answer is b that is -12x^3+12x^2-20

Step-by-step explanation:

<h3>f(x)= -12x^3+19x^2-5</h3><h3>g(x)= 7x^2+15</h3><h3>f(x)-g(x)=(-12x^3+19x^2-5)-( 7x^2+15)...{while opening the bracket the sign of the second polynomial changes accordingly}</h3><h3>it becomes -12x^3+19x^2-5-7x^2-15</h3><h3>=-12x^3+12x^2-20</h3><h3>HOPE IT HELPED UUUU</h3>
7 0
3 years ago
Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Select two options.
Elanso [62]

Answer:

2 and 5

Step-by-step explanation:

The slope-intercept form of a line is y=mx-b where m is slope and b is y-intercept.

The point-slope form of a line is y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.

The standard form a line is ax+by=c.

So anyways parallel lines have the same slope.

So if we are looking for a line parallel to 3x-4y=7 then we need to know the slope of this line so we can find the slope of our parallel line.

3x-4y=7

Goal: Put into slope-intercept form

3x-4y=7

Subtract 3x on both sides:

  -4y=-3x+7

Divide both sides by -4:

   y=\frac{-3}{-4}x+\frac{7}{-4}

Simplify:

   y=\frac{3}{4}x+\frac{-7}{4}

So the slope of this line is 3/4.  So our line that is parallel to this one will have this same slope.

So we know our line should be in the form of y=\frac{3}{4}x+b.

To find b we will use the point that is suppose to be on our new line here which is (x,y)=(-4,-2).

So plugging this in to solve for b now:

-2=\frac{3}{4}(-4)+b

-2=-3+b

3-2=b

b=1

so the equation of our line in slope-intercept form is y=\frac{3}{4}x+1

So that isn't option 1 because the slope is different.  That was the only option that was in slope-intercept form.

The standard form of a line is ax+by=c and we have 2 options that look like that.

So let's rearrange the line that we just found into that form.

y=\frac{3}{4}x+1

Clear the fractions because we only want integer coefficients by multiplying both sides by 4.

This gives us:

4y=3x+4

Subtract 3x on both sides:

-3x+4y=4

I don't see this option either.

Multiply both sides by -1:

3x-4y=-4

I do see this as a option. So far the only option that works is 2.

Let's look at point slope form now.

We had the point that our line went through was (x1,y1)=(-4,-2) and the slope,m, was 3/4 (we found this earlier).

y-y1=m(x-x1)

Plug in like so:

y-(-2)=3/4(x-(-4))

y+2=3/4 (x+4)

So option 5 looks good too.

7 0
3 years ago
Read 2 more answers
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