Answer:
(c) 10m/s
Explanation:
to find the speed of the waves you can use the following formula:
λ: wavelength of the wave
T: period
the wavelength is the distance between crests = 48m
the period is the time of a complete oscillation of the wave. In this case you have that the float takes 2.4 s to go from its highest to the lowest point. The period will be twice that time:
T = 2(2.4s)=4.8s
by replacing you obtain:
the answer is (c) 10m/s
Answer: 4.19 N
Explanation: In order to determinate the tension applied on the wire we have to calculate the electric force between the conductor spheres connected by the wire.
As the wire is a conductor the spheres are at same potential so we have:
V1=V2
V1=k*Q1/r1 and V2=k*Q2/r2
where r1=r2, then
Q1=Q2
so the electric force is given by:
F=k*Q^2/d^2 where d is the distance between the spheres.
Finally replacing the values, we have
F=9*10^9(41*10^-6)^2/(1.9)^2= 4.19 N
Answer:
a) 10 dB, b) 20dB, c) 10², 10⁴, 10⁸
Explanation:
The logarithmic scale has a great advantage when measuring magnitudes of a large number of scales, since it converts these values to linear, allowing easier viewing.
Part A
Let's look for decibels for an intensity I = 10 Io
We calculate
β = 10 log (10Io / Io)
β = 10 dB
Part b
Let's find the intensity for I = 100 Io
We calculate
β = 10 log (100Io / Io)
β = 10 log 100
β = 10 2
β = 20 db
Part c
Δβ2 corresponds to an intensity change of 10² Io, therefore it corresponds to an intensity increase of 10²
Δβ4 corresponds to a change in intensity of 10⁴Io
Δβ8 is an intensity change of 10⁸ Io
Sn is Tin which has 50 atomic number
it means it has 50 electrons in its outer shells
+2 shows its valency
plus sign comes when electrons are removed from an atom
so here 2 electrons are removed from Sn atom
remaining electrons are 50-2
48 electrons