Question

A capacitor consists of two parallel plates, each with an area of 16.0 cm2 , separated by a distance of 0.150 cm . The material that fills the volume between the plates has a dielectric constant of 6.00. The plates of the capacitor are connected to a 400 V battery.

Answer 1

Answer:

Explanation:

Given

area of capacitor $A=16\ cm^2$

Distance between Capacitor $d=0.15\ cm$

dielectric constant $k=6$

Voltage applied $V=400\ V$

Capacitance C is given by $C=k\frac{\epsilon A}{d}$

$C=6\times \frac{8.85\times 10^{-12}\times 16\times 10^{-4}}{0.15\times 10^{-2}}$

$C=56.64\times 10^{-12}\ F$

Charge on Plates

$Q=C\times V$

$Q=56.64\times 10^{-12}\times 400$

$Q=22,656\times 10^{-12}$

$Q=22.656\ nC$