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2 years ago

Almost done please help I’m begging y’all it’s almost time

Mathematics

1 answer:

Nikolay [14]2 years ago

5 0

I believe that it is 2x^2+1x-2

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2abc - 3ab = -30? if a =2, b = -3 and c= 4

velikii [3]

Is your question true or false?

2abc - 3ab = -30? if a =2, b = -3 and c= 4

plug in

2(2)(-3)(4) - 3(2)(-3) = -30

Simplify

-48 + 18 = -30

-30 = -30

Both sides are equal so

It's true.

6 0

3 years ago

Elizabeth performed the geometric construction shown in the diagram. Based on her construction markings we can conclude that the

Alexeev081 [22]

Answer:

A- a regular hexagon

Step-by-step explanation:

5 0

3 years ago

The odds that you will pick a heart from a standard deck of 52 cards is 13:39.

podryga [215]

Not exactly sure but I think it's false hope this helps

3 0

3 years ago

-8 <= 2/5 (k - 2) . . . <= means less than or equal too

oksano4ka [1.4K]

Multiply 5/2 on both sides to clear the fraction.
-8(5/2)=(5/2)(2/5)(k-2)
-20 = k -2
Add 2 to both sides
-18 = k

7 0

3 years ago

What is the inverse of this function?

kolbaska11 [484]

Answer:

$f^{-1}(x)=4x^2-3$

Step-by-step explanation:

The Inverse of a Function

Given a function f(x), the inverse of f, called $f^{-1}(x)$ is a function that satisfies:

$f(f^{-1}(x))=x$

The domain of f becomes the range of its inverse and vice-versa.

The procedure to find the inverse of the function is:

* Write the function as a two-variable equation:

* Solve the equation for x.

* Swap the variables

We are given the function:

$\displaystyle f(x)=-\frac{1}{2}\sqrt{x+3}$

Defined in the interval x ≥ -3

Note f is always negative, thus its range is f(x) ≤ 0

Now we find the inverse. Call y=f(x):

$\displaystyle y=-\frac{1}{2}\sqrt{x+3}$

Multiplying by 2:

$\displaystyle 2y=-\sqrt{x+3}$

Squaring both sides:

$\displaystyle 4y^2=x+3$

Subtracting 3:

$\displaystyle 4y^2-3=x$

Swapping variables:

$y=4x^2-3$

Thus:

$\mathbf{f^{-1}(x)=4x^2-3}$

The domain of the inverse is the range of f, thus x is restricted to

x ≤ 0

5 0

2 years ago