Answer:
f(x) = (x - 7)² - 14
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Vertex Form: f(x) = a(bx - c)² + d
- Completing the Square: (b/2)²
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 14x + 63
<u>Step 2: Rewrite</u>
- Separate: f(x) = (x² - 14x) + 63
- Complete the Square: f(x) = (x² - 14x + 49) + 63 - 49
- Simplify: f(x) = (x - 7)² - 14
We have that
<span>4x -2y =22------> clear variable y
2y=4x-22--------> y=4x/2-22/2---------> y=2x-11-----> equation 1
2x + 4y = 6------> equation 2
substitute equation 1 in equation 2
2x+4*[2x-11]=6-----> 2x+8x-44=6----> 10x=50------> x=5
then
y=2x-11----> y=2*5-11----> y=-1
</span>
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25