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RideAnS [48]
3 years ago
10

Use the following expression to answer the questions: g(to the second power) -4g+6. How many terms are in this expression? What

variable is used in this expression? What is the constant term in this expression?
Mathematics
1 answer:
zmey [24]3 years ago
4 0
G^2-4g+6
# Terms: 3, (g^2), (-4g), (6)
Variable: g
Constant: 6
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Compare the dimensions of the prisms. How many times greater is the surface area of the green prism than the surface area of the
vodomira [7]

Answer:

the green prisim is 5.59 or 5 times bigger!

Step-by-step explanation:

The surface area of the green prisim is 850 and the surface area of the blue one is 150 and 850 divided by 150 is 5.59!

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3 years ago
Cathrine was concerned about her report card grade. She had 5 tests the whole semester. If her scores on each test were 93, 82,
enyata [817]

Answer:

81.6

Step-by-step explanation:

mean/average of her grade = sum of all scores/the number of scores

= (93+82+74+92+67)/5

= 81.6

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3 years ago
A used desktop computer sells for $430, which is 75% reduction from the original price. What was the original price of the compu
sveticcg [70]
The answer will be 752.50
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4 years ago
Given the definitions of f(x) and g(x) below, find the value of g(f(-1)).
Reptile [31]

Answer:

-14

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5 0
2 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Only 1 try
vagabundo [1.1K]

Using the shell method, the volume is

\displaystyle 2\pi \int_0^1 (2-x) \cdot 8x^3 \, dx = 16\pi \int_0^1 (2x^3 - x^4) \, dx

Each cylindrical shell has radius 2-x (the horizontal distance from the axis of revolution to the curve y=8x^3); has height 8x^3 (the vertical distance between a point on the x-axis in 0\le x\le1 and the curve y=8x^3).

Compute the integral.

\displaystyle 16 \pi \int_0^1 (2x^3 - x^4) \, dx = 16\pi \left(\frac{x^4}2 - \frac{x^5}5\right) \bigg|_{x=0}^{x=1} \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 16\pi \left(\frac12 - \frac15\right) \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = \frac{24}5\pi = \boxed{4.8\pi}

6 0
2 years ago
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