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3 years ago

10

Use the following expression to answer the questions: g(to the second power) -4g+6. How many terms are in this expression? What

variable is used in this expression? What is the constant term in this expression?

1 answer:

zmey [24]3 years ago

4 0

G^2-4g+6
# Terms: 3, (g^2), (-4g), (6)
Variable: g
Constant: 6

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Pls help me and give steps as to how to do it thank you

andrew11 [14]

Answer: $x=13, y=132$

Step-by-step explanation:

Using the same-side interior angles theorem, $y=132$ .

Using the alternate interior angles theorem, $5x-17=48 \implies x=13$

7 0

1 year ago

Let Y1 and Y2 be independent exponentially distributed random variables, each with mean 7. Find P(Y1 > Y2 | Y1 < 2Y2). (En

ArbitrLikvidat [17]

<em>Y</em>₁ and <em>Y</em>₂ are independent, so their joint density is

$f_{Y_1,Y_2}(y_1,y_2)=f_{Y_1}(y_1)f_{Y_2}(y_2)=\begin{cases}\frac1{49}e^{-\frac{y_1+y_2}7}&\text{for }y_1\ge0,y_2\ge0\\0&\text{otherwise}\end{cases}$

By definition of conditional probability,

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = P((<em>Y</em>₁ > <em>Y</em>₂) and (<em>Y</em>₁ < 2 <em>Y</em>₂)) / P(<em>Y</em>₁ < 2 <em>Y</em>₂)

Use the joint density to compute the component probabilities:

• numerator:

$P((Y_1>Y_2)\text{ and }(Y_1$

$=\displaystyle\frac1{49}\int_0^\infty\int_{\frac{y_1}2}^{y_1}e^{-\frac{y_1+y_2}7}\,\mathrm dy_2\,\mathrm dy_1$

$=\displaystyle-\frac17\int_0^\infty\int_{-\frac{3y_1}{14}}^{-\frac{2y_1}7}e^u\,\mathrm du\,\mathrm dy_1$

$=\displaystyle-\frac17\int_0^\infty\left(e^{-\frac{2y_1}7} - e^{-\frac{3y_1}{14}}\right)\,\mathrm dy_1$

$=\displaystyle-\frac17\left(-\frac72e^{-\frac{2y_1}7} + \frac{14}3 e^{-\frac{3y_1}{14}}\right)\bigg|_0^\infty$

$=\displaystyle-\frac17\left(\frac72 - \frac{14}3\right)=\frac16$

• denominator:

$P(Y_1$

(I leave the details of the second integral to you)

Then you should end up with

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = (1/6) / (2/3) = 1/4

5 0

2 years ago

A ride-share company has a fee that includes a fixed cost and a cost that depends on both the time spent travelling, in minutes,

zlopas [31]

Answer:

the cost of Roy's ride is $23.05

Step-by-step explanation:

According to the Question,

Let, Cost of per minute charge is 'x' & Cost Of Per Kilometre charge is y .

Given, A ride-share company has a fee of the fixed cost of a ride is $2.55 .
And, The Total cost of the Ride depends on both the time spent on travelling(in minutes), and the distance travelled(in kilometres) .

⇒ Judy's ride costs $16.75 . but the actual cost after deducting the fixed charge is 16.75-2.55 = $14.20, took 8 minutes & The distance travelled was 10 km. Thus, the equation for the journey is 8x+10y=14.20 ⇒ Equ. 1

⇒ Pat's ride costs $30.35 . but the actual cost after deducting the fixed charge is 30.35-2.55 = $27.80, took 20 minutes & The distance travelled was 18 km. Thus, the equation for the journey is 20x+18y=27.80 ⇒ Equ. 2

Now, on Solving Equation 1 & 2, We get

x=0.4(Cost of per minute charge) & y=1.1(Cost Of Per Kilometre charge)

Now, Roy's ride took 10 minutes & The distance travelled was 15 km . Thus, the cost of Roy's Ride is 10x+15y ⇔ 10×0.4 + 15×1.1 ⇔ $20.5

Hence, the total cost of Roy's ride is 20.5 + 2.55(fixed cost) = $23.05

8 0

3 years ago

What is the slope of the line that passes through the points (12,-8) and (-9,-11)

Sauron [17]

Answer: 1/7

Explanation:

1. Use the formula, y2-y1/x2-x1
Plug in the points, (12, -8) and (-9, -11) into the formula.
Point (12, -8): 12 is the X1 and -8 is the y1.
Point (-9, -11): -9 is the X2 and -11 is the y2
So, -11--8/-9-12

2. -11--8/-9-12= -3/-21= 1/7

I hope this helps!!

3 0

3 years ago

9. The ratio of Joe's weight to Colin's is 2:3. Colin's weight is 36kg. If Joe gains

STatiana [176]

2:3
?:36

36/3=13
2x13=26

26:36

26+3=29

29:36

6 0

3 years ago