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RideAnS [48]
3 years ago
10

Use the following expression to answer the questions: g(to the second power) -4g+6. How many terms are in this expression? What

variable is used in this expression? What is the constant term in this expression?
Mathematics
1 answer:
zmey [24]3 years ago
4 0
G^2-4g+6
# Terms: 3, (g^2), (-4g), (6)
Variable: g
Constant: 6
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Illustrate the distributive property to solve 144/8
AURORKA [14]

Answer:

8 (19) or  8 (18 +1)

Step-by-step explanation:

Distributive property means to distribute.

HCF of 144 and 8.

=> 8 is the HCF of 144 and 8

8 (18 + 1)

=> 8 (19)

4 0
3 years ago
PLease help! u can make it short i'm in a rush. please help me
Sergeeva-Olga [200]
The correct answer is A !
5 0
3 years ago
the area of a rectangular back yard is given by the trinomial b^2+5b-24. What are possible dimensions of the backyard?
yanalaym [24]
B^2+5b-24 Using the AC method for factoring (b+8)(b-3)
4 0
3 years ago
Find the angle between the hands of a clock at 5:15<br><br> A 60<br> B 67.5<br> C 75
Viktor [21]

Answer:

Option B is correct.

67.5 degree

Step-by-step explanation:

To find the angle between the hands of a clock.

Given that:

Hands of a clock at 5 : 15.

We know that:

A clock is a circle and it always contains 360 degree.

Since, there are 60 minutes on a clock.

\frac{360^{\circ}}{60 minutes} = 6^{\circ} per minutes

so,  each minute is 6 degree.

The minutes hand on the clock will point at 15 minute,

then, its position on the clock is:

(15) \cdot 6^{\circ} = 90^{\circ}

Also, there are 12 hours on the clock

⇒Each hour is 30 degree.

Now, can calculate where the hour hand at 5:00 clock.

⇒5 \cdot 30 =150^{\circ}

Since, the hours hand is between 5 and 6 and we are looking for 5:15 then :

15 minutes is equal to \frac{1}{4} of an hour

⇒150+\frac{1}{4}(30) = 150+7.5 = 157.5^{\circ}

Then the angle between two hands of clock:

⇒\theta = 150.75 -90 = 67.5^{\circ}

Therefore, the angle between the hands of a clock at 5: 15 is: 67.5 degree.

4 0
3 years ago
Read 2 more answers
What set of reflections and rotations would carry rectangle ABCD onto itself? Parallelogram formed by ordered pairs A at negativ
Hoochie [10]

Answer:

Option (4).

Step-by-step explanation:

Let's take the coordinates of point A for the set of reflections and rotations given in the options.

Option (1). Rotate 180° → A(-4, 1) becomes (4, -1)

                Reflect over x-axis → (4, -1) becomes (4, 1)

                Reflect over the line y = x → (4, 1) becomes A'(1, 4)

Therefore, point A will not overlap itself after the number of transformations given.

Option (2). Reflect across x-axis → A(-4, 1) will become (-4, -1)

                  Rotate 180° → (-4, -1) becomes (4, 1)

                  Reflect over the x-axis → (4, 1) becomes A'(4, -1)

Therefore, point A(-4, 1) doesn't overlap A'(4, -1).

Option (3). Rotate 180° → A(4, 1) becomes (-4, -1)

                  Reflect over the y-axis → (-4, -1) becomes (4, -1)

                  Reflected over y = x → (4, -1) becomes (-1, 4)

So the point A(4, 1) becomes A'(-1, 4) after the set of reflections,

Option (4). Reflect over the y axis → A(-4, 1) becomes (4, 1)

                 Reflect over the x-axis → (4, 1) becomes (4, -1)

                 Rotate 180° → (4, -1) becomes A'(-4, 1)

Therefore, point A will overlap itself following the set of transformations.

6 0
3 years ago
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