Question

The access code for a​ car's security system consists of six digits. The first digit cannot be zero and the last digit must be odd . How many different codes are​ available? (Note that 0 is considered an even​ number.)

Answer 1

Answer:

67200

Step-by-step explanation:

We are given that the access code for a car's security system consist of six digits.

First digit cannot be zero and the last digit must be odd.

We have available digits which can used from 0 to 9.

We have to find the number of different codes are available without replacement.

Total odd digits=1,3,5,7,9=5

The sixth place place can be filled by number of ways=5

The first place can be filled by number of ways=8

The second place filled by number of ways=8

The third place can be filled by number of ways=7

The fourth place can be filled by number of ways=6

The fifth place can be filled by number of ways=5

Therefore, the total number of different codes are available=$5\times 8\times 8\times 7\times 6\times 5=67200$

Answer:67200