The access code for a car's security system consists of six digits. The first digit cannot be zero and the last digit must be o
1 answer:
Answer:
67200
Step-by-step explanation:
We are given that the access code for a car's security system consist of six digits.
First digit cannot be zero and the last digit must be odd.
We have available digits which can used from 0 to 9.
We have to find the number of different codes are available without replacement.
Total odd digits=1,3,5,7,9=5
The sixth place place can be filled by number of ways=5
The first place can be filled by number of ways=8
The second place filled by number of ways=8
The third place can be filled by number of ways=7
The fourth place can be filled by number of ways=6
The fifth place can be filled by number of ways=5
Therefore, the total number of different codes are available=
Answer:67200
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Answer:
(a) 720 ways
(b) 120 ways
(c) 24 ways
Step-by-step explanation:
Given
--- number of letters
Solving (a): Number of arrangements.
We have:
So, the number of arrangements is calculated as:
This gives:
This gives:
Solving (b): DA as a unit
DA as a unit implies that, we have:
[DA] N C E R
So, we have:
So, the number of arrangements is calculated as:
This gives:
This gives:
Solving (c): NCE as a unit
NCE as a unit implies that, we have:
D A [NCE] R
So, we have:
So, the number of arrangements is calculated as:
This gives:
This gives: