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marta [7]
3 years ago
5

Molly is designing a dog house for her puppy that has a rectangular base. The length of the base is 7 inches more than its width

. She wants the area of the base to be greater than 375 square inches. If w represents the width of the doghouse, write the inequality that can be used to determine the possible dimensions of the base of the dog house.
Mathematics
2 answers:
juin [17]3 years ago
6 0

7w2+7w<375 hope this helped

Mariana [72]3 years ago
5 0

We assume w is the number of <em>inches</em> of width (as opposed to <em>feet</em> or some other measure). The length is 7 inches more than the width, so is w+7. The area is the product of these dimensions, and the problem statement tells us that area is greater than 375 in².

... w(w+7) > 375 . . . . . the inequality that can be used to find dimensions

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Solve the equation... 10x - 12 = 48 - 2x
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If you would like to solve the equation 10 * x - 12 = 48 - 2 * x, you can calculate this using the following steps:

10 * x - 12 = 48 - 2 * x
10 * x + 2 * x = 48 + 12
12 * x = 60   /12
x = 60 / 12
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The correct result is 5. 
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3 years ago
Last questions, plz help
Goryan [66]

Answer:

9. a_n=7+6n

10. a_n=a_{n-1}+7

Step-by-step explanation:

9. Given the sequence

13, 19, 25, ...

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a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...

Note that

a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,

then the common difference in this sequence is d=6

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a_1=13\\ \\d=6,

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a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n

10. Given the sequence

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In this sequence,

a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...

Note that

a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,

then the common difference in this sequence is d=7

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a_1=-10\\ \\d=7,

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a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7

5 0
3 years ago
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6 0
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Step-by-step explanation:

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3 years ago
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Anit [1.1K]
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therefore the cost will be $3937.5
8 0
2 years ago
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