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Sergio [31]
3 years ago
7

g Given the following premises: (1) a∧(b∨a) (2) ~c→~a (3) ~g→~a (4) g→e (5)~(d∨h) Prove the Conclusion: c∧~h?

Mathematics
1 answer:
KIM [24]3 years ago
8 0

Answer:

See the argument below

Step-by-step explanation:

I will give the argument in symbolic form, using rules of inference.

First, let's conclude c.

(1)⇒a  by simplification of conjunction

a⇒¬(¬a) by double negation

¬(¬a)∧(2)⇒¬(¬c) by Modus tollens

¬(¬c)⇒c by double negation

Now, the premise (5) is equivalent to ¬d∧¬h which is one of De Morgan's laws. From simplification, we conclude ¬h. We also concluded c before, then by adjunction, we conclude c∧¬h.

An alternative approach to De Morgan's law is the following:

By contradiction proof, assume h is true.

h⇒d∨h by addition

(5)∧(d∨h)⇒¬(d∨h)∧(d∨h), a contradiction. Hence we conclude ¬h.    

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EastWind [94]

Answer: Option C.

Step-by-step explanation:

The lengths of our triangle are:

9, 10 and √130.

If the triangle is a triangle rectangle, by the Pitagoream's theorem we have:

A^2 + B^2 = H^2

in this case H is the larger side, this must be √130.

then:

A and B must be 9 and 10.

9^2 + 10^2 = (√130)^2

81 + 100 = 130

This is false, so this is NOT a triangle rectangle, the hypotenuse is shorter than it should be.

Now, we have some kind of rule:

 if A^2 + B^2 = H^2 then we have one angle of 90° and two smaller ones. (triangle rectangle)

 if A^2 + B^2 > H^2 then all the angles are smaller than 90°, this is an acute triangle.

 if A^2 + B^2 < H^2 then we have one angle larger than 90°, this is an obtuse angle.

(H is always the larger side, A and B are the two shorter ones).

In this case:

81 + 100 > 130

Then this must be an acute angle.

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3 years ago
Simplify. 2 - 30 × 5
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ollegr [7]

<u>Given</u>:

The sides of the base of the triangle are 8, 15 and 17.

The height of the prism is 15 units.

We need to determine the volume of the right triangular prism.

<u>Area of the base of the triangle:</u>

The area of the base of the triangle can be determined using the Heron's formula.

S=\frac{a+b+c}{2}

Substituting a = 8, b = 15 and c = 17. Thus, we have;

S=\frac{8+15+17}{2}

S=\frac{40}{2}=20

Using Heron's formula, we have;

Area = \sqrt{S(S-a)(S-b)(S-c)}

Area = \sqrt{20(20-8)(20-15)(20-17)}

Area = \sqrt{20(12)(5)(3)}

Area = \sqrt{3600}

Area = 36

Thus, the area of the base of the right triangular prism is 36 square units.

<u>Volume of the right triangular prism:</u>

The volume of the right triangular prism can be determined using the formula,

V=\frac{1}{2}A_b h

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