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2 years ago

What is the perimeter? 8 m 4 m 4 m 12 m meters Submit

Mathematics

1 answer:

lilavasa [31]2 years ago

7 0

Add all of the numbers together, 28m is the final answer

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(the stake is 14ft)

Kaylis [27]

Answer:

it‘s about

32.08 ft (if its not an answer choice try 32 or anywhere near that number)

Step-by-step explanation:

SO this is a simple example of triangles

We would need to find the heigh of the flagpole which is the leg of the triangle

The other side (14ft) is the 2nd leg of the triangle

And we know the hypotenuse is 35 ft

So we put that in Pythagorean Theroux and solve for the first missing leg

a^2+14^2=35^2

a^2+196=1225

a^2=1029

√1029 is about 32.08

So its about 32.08

5 0

3 years ago

What is 1 + 1 i need help.

Anastasy [175]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Help ASAP!! QR is the median of trapezoid MNOP. If MN = 41 and OP = 53, calculate QR.

stealth61 [152]

Answer:

QR = 86

Step-by-step explanation:

<em>Trust.</em>

5 0

3 years ago

Read 2 more answers

How<br> Do you graph 2x+8y=-32

Neporo4naja [7]

First, subtract 2x from both sides of the equation to get 8y = -2x - 32. Then, divide the equation by 8, to get y = -x/4 - 4. Your y-intercept will be -4, and it's slope will be -1/4.

5 0

3 years ago

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!

$T = (-1250(0))-(-1250e^0)$

$T = 1250$

this is the total amount of waste

6 0

3 years ago