Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
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Next time, please share your system of linear equations by typing only one equation per line:
<span>3x - 2y - 7 = 0 5x + y - 3 = 0 NO
</span><span>3x - 2y - 7 = 0
5x + y - 3 = 0 YES
Mult. the 2nd equation by 2 so as to obtain 2y, which will be cancelled out by - 2y in the first equation:
</span><span> 3x - 2y - 7 = 0
2(5x + y - 3 = 0)
Then:
3x - 2y - 7 = 0
10x +2y - 6 = 0
----------------------
13x - 13 = 0, so that x = 1. Find y by subbing 1 for x in either of the 2 given equations.</span>
Answer: a
Step-by-step explanation:
Answer:
y = 5x+7
Step-by-step explanation:
Parallel lines have the same slope so y = 5x+9 is in slope intercept form
y = mx+b where m is the slope and b is the y intercept
The slope is 5
The new line will have a slope of 5
y = 5x+b
We know a point on the line (-2,-3)
Substitute this point into the equation
-3 = 5(-2)+b
-3 = -10+b
-3+10 = b
7 = b
y = 5x+7
