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cricket20 [7]
3 years ago
7

A square on a coordinate plane has the points A(0, 0), B(0, 5), C(5, 5) and D(5, 0). If Square ABCD is rotated about the origin

180 degrees clockwise to form Square A'B'C'D', what would be the length of one of the sides? A. 0 units B. 5 units C. 10 units D. 20 units
Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

B. 5 units

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, dilation, rotation or translation.

If a point X(x,y) is rotated about the origin 180 degrees clockwise the new point is at X'(-x, -y).

If the square with vertices at A(0, 0), B(0, 5), C(5, 5) and D(5, 0) is rotated about the origin 180 degrees clockwise the new points are at A'(0, 0), B'(0, -5), C'(-5, -5), D'(-5, 0)

A square has four equal sides. The distance between two points X(x_1,y_1)\ and\ Y(x_2,y_2) is:

|XY|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Hence:

|A'B'|=\sqrt{(0-0)^2+(-5-0)^2} =5

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Check all that are true.

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What is the argument of -5\sqrt{3}+ 5i?
Shtirlitz [24]

Answer:

150 degrees

Step-by-step explanation:

Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.

So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length 5\sqrt{3}. The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.

Let's find the complementary angle.

So the opposite side of the complementary angle is 5.

The adjacent side of the complementary angle is 5\sqrt{3}.

\tan(\theta)=\frac{5}{5\sqrt{3}}

\tan(\theta)=\frac{1}{\sqrt{3}}

\theta=\tan^{-1}(\frac{1}{\sqrt{3}})

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3 years ago
What is the area of this trapezoid?
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Answer:

132 in

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3 years ago
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