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2 years ago

9

Write each equation in slope-intercept form. Identify the slope and y-intercept. Then graph the line described by the question.

(If possible please show work)

1 answer:

Rasek [7]2 years ago

6 0

Answer:

Step-by-step explanation:

Equation of the line is,

y = -x + 2

By comparing this equation with,

y = mx + b

Here, m = slope of the line

b = y-intercept

Therefore, slope of the line given in the graph = (-1)

y-intercept = 2

Now we will find the table for the points lying on the line,

x -6 -4 0 4 6

y 8 6 2 -2 -4

Now plot these points on the graph and join them to get the line.

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9- (-4) =<br> 14 -9 =<br> (-4) - (-5) =<br> -7 - 9 =

AlekseyPX

Answer:

Step-by-step explanation:

9 + 4 = 13 Two minus' make a plus

14-9 = 5 this is just subtraction

-4 + 5 = 1 two minus's make a plus.

-7-9 = -16

3 0

3 years ago

Write the slope-intercept form of the equation of the line described.

Ad libitum [116K]

7)

Given the line

$y=-x+2$

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = -1

We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -1 and the point (4, 0)

$y-0 = -1 (x-4)$

Writing in the slope-intercept form

$y = -x+4$

Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:

$y = -x+4$

8)

<em>Note: </em><em>Your line is a little bit unclear. But, I am assuming the</em>

<em>ine is: </em>y = -x-1

<em />

Given the assumed line

y = -x-1

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = m = -1

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -1

perpendicular slope = – 1/m = -1/-1 = 1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1 and the point (4, 3)

$y - 3 = 1 (x-4)$

Writing in the slope-intercept form

y-3 = x-4

y = x-4+3

y = x - 1

Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:

y = x - 1

5 0

2 years ago

What is the exact value of BC?<br>A. 3.16<br>B. 5\|2<br>C. 7.07<br>D. 25<br>

Natalija [7]

Answer:

$C. \: \: 7.07$

Step-by-step explanation:

Coordinates of B are

$(5,5)$

Coordinates of C are

$(4, - 2)$

Distance between two points

$\sqrt{({x_2 - x _1 {)}^{2} + (y_2 - y_1 {)}^{2} }}$

Distance of BC

$\sqrt{(4 - 5) {}^{2} + ( - 2 - 5 {)}^{2} }$

$\sqrt{ { (- 1}^{2}) + ({ - 7}^{2}) }$

$\sqrt{1 +49 }$

$\sqrt{50}$

$7.07$

3 0

2 years ago

WHICH PROPERTY IS BEING USED IN THE FOLLOWING? <br><br>15 × 1 = 15

Andrews [41]

Answer:

This is the Idenity Property

Step-by-step explanation:

The Identity Property for multiplication states that anything times 1 is the same number.

3x1=3, and 8192x1=8192 (Do you play 2048?)

The zero property: Anything multiplied by zero is zero.

1000000000000000000000000000000x0=0, 4096 x 0 = 0, and so on.

The associative property: Any where numbers are grouped in parenthesis or brackets, you still get the same answer.

(6 x 7) x 78 is the same as 6 x (7 x 78)

The commutative property: When you switch the order of numbers, you get the same answer.

256 x 32 is the same as 32 x 256

4 0

2 years ago

How do I solve for x here? Use the properties of logarithms to find a value for x. Assume a,b, and M are constants.

Leona [35]

Yes, you're right! The first step is rewriting the equation as

$\ln(a) + \ln(b^x) = M$

Subtract $\ln(a)$ from both sides:

$\ln(b^x) = M-\ln(a)$

Use the property $\ln(a^b) = b\ln(a)$ to rewrite the equation as

$x\ln(b) = M-\ln(a)$

Divide both sides by $\ln(b)$

$x = \dfrac{M-\ln(a)}{\ln(b)}$

Alternative strategy:

Consider both sides as exponents of e:

$e^{\ln(ab^x)} = e^M$

Use $e^{\ln(x)} = x$ to write

$ab^x = e^M$

Divide both sides by a:

$b^x = \dfrac{e^M}{a}$

Consider the logarithm base b of both sides:

$x = \log_b\left(\dfrac{e^M}{a}\right)$

The two numbers are the same: you can check it using the rule for changing the base of logarithms

7 0

3 years ago