√75 + √3
5√3 + √3
√3(5 + 1)
6√3
In short, Your Answer would be 6√3
Hope this helps!
Answer:
Step-by-step explanation:
<u>Question 1</u>
<u>Part (a)</u> :
⇒ 6 × 6 × 6 × 6 × 6 × 6 × 6 = 6ˣ
⇒ 6⁷ = 6ˣ
⇒ x = 7
<u>Part (b)</u> :
⇒ y² = 169
⇒ √y² = √169
⇒ y = ± 13
⇒ y = 13, y = -13
<u>Question 2</u>
<u>Part (a)</u> :
⇒ (√5)² × (√3)²
⇒ 5 × 3
⇒ 15
<u>Part (b)</u> :
⇒ (∛9)³ × (√30)²
⇒ 9 × 30
⇒ 270
Answer:
If you write a number as a fraction, that number's reciprocal is a fraction with the numerator and the denominator switched around. For example, the reciprocal of
4
5
is
5
4
. Some general rules to keep in mind:
-If the fraction has a
0
in the numerator, the reciprocal is undefined.
-If the fraction has a
0
in the denominator, the fraction itself is undefined. Thus it can't have a reciprocal.
-Any other fraction has exactly one reciprocal.
Finally, the reciprocal of a reciprocal is the original fraction. This means if you flip a fraction's numerator and denominator, and then flip them back, you get the number you started with.
Step-by-step explanation:
Answer:
Hello if I know the answers to your math questions I'll answer if there already posted.
Step-by-step explanation:
