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ELEN [110]
3 years ago
6

If f(x)=-3x+4 and g(x)=x2, what is (g°f)(0)

Mathematics
2 answers:
Rus_ich [418]3 years ago
6 0

Answer:

16

Step-by-step explanation:

Eva8 [605]3 years ago
6 0

Answer:

(g\circ f)(0)=16

Step-by-step explanation:

The given functions are

f(x)=-3x+4 and g(x)=x^2

We first find the composition; (g\circ f)(x)

(g\circ f)(x)=g(f(x))

(g\circ f)(x)=g(-3x+4)

(g\circ f)(x)=(-3x+4)^2

We now plug in x=0, to obtain;

(g\circ f)(0)=(-3(0)+4)^2

(g\circ f)(0)=(4)^2

(g\circ f)(0)=16

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Write an equation of the line passing through the point A(2, 0) that is parallel to the line y = 3x−5
satela [25.4K]

Answer:

y = 3x-6

Step-by-step explanation:

y = 3x−5

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m =3

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Substituting the point into the equation to solve for b

0 = 3(2)+b

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3 years ago
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Oksana_A [137]

Answer:

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Step-by-step explanation:

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Write the equation for a parabola with a focus at (6,-4) and a directrix at y= -7
shtirl [24]

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

y=\dfrac{1}{4p}(x-h)^2+k                  ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

(h,k+p)=(6,-4)

On comparing both sides, we get

h=6

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Directrix at y=-7. So,

k-p=-7                            ...(iii)

Adding (ii) and (iii), we get

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Putting k=-5.5 in (ii), we get

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Putting h=6, k=-5.5,p=1.5 in (i), we get

y=\dfrac{1}{4(1.5)}(x-6)^2+(-5.5)

y=\dfrac{1}{6}(x-6)^2-5.5

Therefore, the equation of the parabola is y=\dfrac{1}{6}(x-6)^2-5.5.

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2 years ago
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Step-by-step explanation:

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