Question

If f(x)=-3x+4 and g(x)=x2, what is (g°f)(0)

Answer 1

Answer:

16

Step-by-step explanation:

Answer 2

Answer:

$(g\circ f)(0)=16$

Step-by-step explanation:

The given functions are

$f(x)=-3x+4$ and $g(x)=x^2$

We first find the composition; $(g\circ f)(x)$

$(g\circ f)(x)=g(f(x))$

$(g\circ f)(x)=g(-3x+4)$

$(g\circ f)(x)=(-3x+4)^2$

We now plug in x=0, to obtain;

$(g\circ f)(0)=(-3(0)+4)^2$

$(g\circ f)(0)=(4)^2$

$(g\circ f)(0)=16$