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3 years ago

Evaluate.

Mathematics

1 answer:

const2013 [10]3 years ago

6 0

9514 1404 393

Answer:

-1/6

Step-by-step explanation:

A suitable calculator can evaluate this for you and show you the result as a fraction.

You start with the multiplication in the inner-most set of brackets. Here, those brackets are the absolute value function.

-2(-1/3) = +2/3

Then the sum in those brackets:

-5/6 +2/3 = -5/6 +4/6 = -1/6

The absolute value changes the sign of this back to positive, so the value in square brackets is ...

3 -(1/6) = 18/6 -1/6 = 17/6

Finally, this value is divided by -17, so you have ...

$\dfrac{17}{6}\div(-17)=\dfrac{17}{6}\cdot\dfrac{-1}{17}=-\dfrac{17\cdot1}{17\cdot6}=\boxed{-\dfrac{1}{6}}$

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From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri

Leviafan [203]

Answer:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=201.77$ represent the sample mean

$s=2.41$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =200$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :

Null hypothesis: $\mu = 200$

Alternative hypothesis: $\mu = 200$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

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3 years ago

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The answer is B.

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3 years ago

Tim explained a function in words and Paul wrote an equation. Tim The amount of money in Marshas savings account increases at a

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Answer:

Tim has the smaller y-intercept = 2780

Step-by-step explanation:

Tim explains that Marshas saving increases by 225 per month. After 8 months, Marsha's has 4580 in his account.

Let m be the gradient(change per month)

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Let y1 be the amount in Marsha's account after 8 months

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Let x be the initial month d money was put into the account.

Let x1 be the number of months it takes for money to increase to 4580

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y = 225x + 2780

Comparing with y = mx + c, c(intercept) = 2780

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y - 1400 = 56(x + 26)

y -1400 = 56x + 1456

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Therefore comparing Tim's Y intercept and Paul's Y intercept,

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Step-by-step explanation:

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