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maxonik [38]
3 years ago
10

MULTIPLY

%7Ba%5E%7B2%7D-9%20%7D%7Ba%7D" id="TexFormula1" title="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" alt="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" align="absmiddle" class="latex-formula">

Mathematics
2 answers:
Reika [66]3 years ago
8 0

hope this helps youuu!!!!

Oksana_A [137]3 years ago
5 0
The answer should be
(9(a^2)-27a)/(a+3)
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Solve 3(5x-4) < 15x
ollegr [7]

Answer:

All real numbers

Step-by-step explanation:

3(5x - 4) < 15x

~Distribute left side

15x - 12 < 15x

~Subtract 15x to both sides

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Best of Luck!

5 0
3 years ago
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Write the equation of the circle with center (-4, 8) and passes through the point (-2, -1)
anzhelika [568]

Answer:

(x+4)^2+(y-8)^2=85

Step-by-step explanation:

The standard equation for a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (h, k) is the center and r is the radius.

We know that the center is (-4, 8). So, substitute -4 for h and 8 for k:

(x-(-4))^2+(y-8)^2=r^2\\

Simplify:

(x+4)^2+(y-8)^2=r^2

Now, we will need to find r.

We know that it passes through the point (-2, -1). So, we can substitute -2 for x and -1 for y and solve for r. So:

(-2+4)^2+(-1-8)^2=r^2

Evaluate:

(2)^2+(-9)^2=r^2

Square:

4+81=r^2

Add:

r^2=85

So, r squared is 85.

We don’t actually have to solve for r itself, since we will have to square it anyways.

So, we have:

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Substituting 85 for r squared, we get:

(x+4)^2+(y-8)^2=85

And we have our equation.

8 0
3 years ago
What’s the slope of (8,4) and (6,5)
Volgvan

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3 years ago
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What is the slope of the line?
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7 0
3 years ago
Find the absolute maximum and minimum of the function f(x)=sin^2x+cosx
rosijanka [135]
Hello : 
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f'(x) = 0  :  sin(x) (2cos(x) - 1) = 0
sin(x) = 0 : x = k <span>π    k in Z
</span>2cos(x) - 1 =0 : 2cos(x) =1
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3 years ago
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