Ask question

Ask question

All categories

3 years ago

10

MULTIPLY

%7Ba%5E%7B2%7D-9%20%7D%7Ba%7D" id="TexFormula1" title="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" alt="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" align="absmiddle" class="latex-formula">

2 answers:

Reika [66]3 years ago

8 0

hope this helps youuu!!!!

Oksana_A [137]3 years ago

5 0

The answer should be
(9(a^2)-27a)/(a+3)

You might be interested in

Plz I need help on #12

Lorico [155]

Answer:

C its C

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The number 68 is increased to 73. What is the percentage by which the number was

Murljashka [212]

Answer: 1.1%

Step-by-step explanation:

To get a percentage you want to divide the ending number by the base number

73 / 68 = 1.07

It says to round to the neartest tenth, when rounding if the number is 5 or above you round up, if under 5 your number stays the same

7 is higher than 5 so we round up

1.1%

3 0

3 years ago

Pete, a professional bowler, is unhappy with any game below 200. Over time, 80% of his games exceed this score. What is the prob

Aneli [31]

The probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

It has a range of 0 to 1.

It is given that

Pete, a professional bowler, is unhappy with any game below 200

80% of his games exceed this score.

the probability that Pete exceeds 200 in at least 9 of his next 10 games is given by

P( 9/10 > 200) +P(10/10>200)

The binomial experiment consists of n trial out of it x is success.

$P( x) = \dfrac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$

Here p = 0.8

For 9/10 matches

$P( 9/10 > 200) = \dfrac{10!}{9!(10-9)!}0.8^9(1-0.8)^{10-9}\\\\ = {10}(0.8)^9(0.2)\\= 0.268$

For (10/10 >200)

$P( 10/10 > 200) = \dfrac{10!}{10!(10-10)!}0.8^{10} (1-0.8)^{10-10}\\\\ = {1!}(0.8)^{10}\\= 0.1074$

Therefore the probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754.

To know more about Probability

brainly.com/question/11234923

#SPJ1

5 0

2 years ago

Choose Equivalent or Not Equivalent <br><br> a. 6(3x+5) and 18x+30 <br><br> b. 12y+3 and 3y+12

ELEN [110]

I think it is B
Hope my answer help you?

5 0

3 years ago

Read 2 more answers

Edurado started a business selling sporting goods.He spent $ 7500 to obtain hos merchandise , and it cost him $300 per week for

Alik [6]

Answer:

C) It will take 14 weeks for Edurado to make a profit.

Step-by-step explanation:

The money spent on obtaining the merchandise = $ 7500

The general expense per week = $300

Let us assume Eduardo has to work for N weeks to break Even.

So, the general expense in N weeks = N x( Expense per week)

= N x ( $300) = 300 N

So, the total expense in N weeks = Money spent on merchandise + general expense

or, the TOTAL EXPENSE = $ 7500 + 300 N .... (1)

Now, the earning per week = $850

So, the total earning in N weeks = N x ( Earning in 1 week) = N x ( $850)

or, the TOTAL EARNING = 850 N .... (2)

Now, for N weeks ,

TOTAL EXPENSE = TOTAL EARNING

⇒ $7500 + 300 N = 850 N

or, 7500 = 850 N - 300 N = 550 N

⇒ N = 7500/550 = 13.63

So, number of weeks should at least be 13.63

Among the given options, N = 14 weeks is the most feasible answer.

Hence, it will take 14 weeks for Edurado to make a profit.

5 0

3 years ago