MULTIPLY
%7Ba%5E%7B2%7D-9%20%7D%7Ba%7D" id="TexFormula1" title="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" alt="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" align="absmiddle" class="latex-formula">
2 answers:
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Answer:
0.0764
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What proportion of boxes is underweight (i.e., weigh less than 32 oz)?
This is the pvalue of Z when X = 32. So
has a pvalue of 0.0764, which is the correct answr