MULTIPLY
%7Ba%5E%7B2%7D-9%20%7D%7Ba%7D" id="TexFormula1" title="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" alt="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" align="absmiddle" class="latex-formula">
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Answer:
Step-by-step explanation:
The standard equation for a circle is given by:
Where (h, k) is the center and r is the radius.
We know that the center is (-4, 8). So, substitute -4 for h and 8 for k:
Simplify:
Now, we will need to find r.
We know that it passes through the point (-2, -1). So, we can substitute -2 for x and -1 for y and solve for r. So:
Evaluate:
Square:
Add:
So, r squared is 85.
We don’t actually have to solve for r itself, since we will have to square it anyways.
So, we have:
Substituting 85 for r squared, we get:
And we have our equation.