MULTIPLY
%7Ba%5E%7B2%7D-9%20%7D%7Ba%7D" id="TexFormula1" title="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" alt="\frac{9a^{2} }{a^{2} +6a+9} *\frac{a^{2}-9 }{a}" align="absmiddle" class="latex-formula">
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Answer:
<h2>50°</h2>Step-by-step explanation:
AB = AC
So, it is a isosceles triangle.
<B = <C = 65°
Sum of angles of triangle = 180°
< A + < B + <C = 180°
plug the values:
X + 65° + 65° = 180°
Calculate the sum
X + 130° = 180°
Move constant to R.H.S and change its sign
x = 180° - 130°
Calculate the difference
X = 50°
Hope this helps...
Good luck on your assignment...
