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ziro4ka [17]
3 years ago
6

Mark owns Siberian Husky sled dogs. He knows from data collected over the years that the weight of the dogs is a normal distribu

tion. They have a mean weight of 52.5 lbs and a standard deviation of 2.4 lbs. What percentage of his dogs would you expect to have a weight between 47.7 lbs and 54.9 lbs?
Mathematics
1 answer:
kozerog [31]3 years ago
8 0
Calculate the z-score for the given data points in the item using the equation,
 
                             z-score = (x - μ) / σ

where x is the data point, μ is the mean, and σ is the standard deviation.

Substituting,
             (47.7)     z-score = (47.7 - 52.5)/2.4 = -2

This translates to a percentile of 2.28%.

              (54.9)      z-score = (54.9 - 52.5)/2.4 = 1

This translates to a percentile of 84.13%. 

Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em> 

Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs. 
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Fiona divided 3x2 + 5x – 3 by 3x +2. The expression represents the remainder over the divisor. x + 1 + What is the value of a?
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(x^2-1)(4x^3-3x^2+5)
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Anwser: 4x^5-3x^4-4x^3+8x^2-5

Step-by-step explanation:

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A wool sweater originally costs $42.00. if the sweater is on sale for 25% off, what is the new cost of the sweater? $
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Each contestant in the Hunger Games must be trained to compete. Suppose that the time it takes to train a contestant has mean 5
LiRa [457]

Answer:

11.51% probability that it will take less than 450 days to train all the contestants.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n variables, the mean is \mu*n and the standard deviation is s = \sigma\sqrt{n}

In this question:

n = 100, \mu = 100*5 = 500, s = 4\sqrt{100} = 40

Approximate the probability that it will take less than 450 days to train all the contestants.

This is the pvalue of Z when X = 450.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{450 - 500}{40}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

11.51% probability that it will take less than 450 days to train all the contestants.

8 0
4 years ago
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