Answer:
<em>Choose the first alternative</em>

Step-by-step explanation:
<u>Probabilities</u>
The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions
and the total number of possible choices
, i.e.

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total
We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.
To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

The total number of possible choices is

The probability is then

Choose the first alternative
The equation would be 30+3m=162 then you solve the problem
Answer: 0.4x = 3 is the answer
Step-by-step explanation:
Answer:
0.815
Step-by-step explanation:
First, find the z-scores.
z = (x − μ) / σ
z₁ = (8 − 10) / 1
z₁ = -2
z₂ = (11 − 10) / 1
z₂ = 1
P(-2 < Z < 1) = P(Z < 1) − P(Z < -2)
Use a chart, calculator, or the empirical rule to find the probability.
Using the empirical rule:
P(-2 < Z < 1) = 0.84 − 0.025
P(-2 < Z < 1) = 0.815
Using a chart:
P(-2 < Z < 1) = 0.8413 − 0.0228
P(-2 < Z < 1) = 0.8185
Answer:
71
Step-by-step explanation: