1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
B
Step-by-step explanation:
you can use foil and the graph,
because you can see (in the graph) that the lines intersect at 1 and 4.
just use foil to help figure out which matches the slope.
something else (the normal way) is find which 2 numbers equal to the last coefficient, in this case it can be
-2 and -2, 2 and 2, 4 and 1 or -4 and -1, multiply them and if they make up the last coefficient, and added it equals the second coefficient it is correct.
Answer:30 feet.
Step-by-step explanation: 2 doubled is four and in the bigger triangle it says 5. Therefore 12 doubled and a bit more is 30
35/8 = 4.376 5/3 = 1.666… 4.376/1.666…
Therefore 2.625 pieces
Answer:
10.5 I think
Step-by-step explanation:
(1/2) *12 is 6
(1/2)*21 is 10.5
