I'm not sure if I'm missing part of your question but it seems like you didn't provide the ordered pairs to choose from.
Answer:
d im pretty sure
Step-by-step explanation:
srry if this is wrong
To get the simplest radical root form for a non-perfect square, always factor out the number first.
So, for 18, find the factors.
18
6 3
2 3 3
2 3²
so, when you find a pair of the same two numbers, they become squared. Eliminate the squared signs; that number goes to the left, and the left over numbers are multiplied and are put into the square root sign. So, you end up with the final answer:
3
Answer:
1)6x^2+7x-24
2) x-4
3) f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7
f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-15
4)f'(x)=(x-7)/3
Step-by-step explanation:
1) f(x)=2x-3 g(x)=3x+8
f(x)*g(x)=m(x)=(2x-3)(3x+8)=6x^2+16x-9x-24=6x^2+7x-24
2) f(x)=x^2+x-20 g(x)=x+5
f(x)/g(x)=p(x)=(x^2+x-20)/(x+5)=> by finding the roots of f(x) we obtain =
(x-4)(x+5)/(x+5)--->f(x)/g(x)=p(x)=(x-4)
3) f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7
f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-15
4) If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back x
y=3x+7
(y-7)/3=x=--> f'(x)=(x-7)/3
Answer: The answer should be C if you were to add each point.