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Alenkinab [10]
3 years ago
6

The given line segment has a midpoint at (-1, -2).

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

Answer:

  y = -4x -6

Step-by-step explanation:

The given segment has a rise if 1 for a run of 4, so a slope of ...

  m = rise/run = 1/4

The desired perpendicular has a slope that is the negative reciprocal of this:

  m = -1/(1/4) = -4

A point that has a rise of -4 for a run of 1 from the given midpoint is ...

  (-1, -2) +(1, -4) = (0, -6) . .  . . . . . the y-intercept of the bisector

So, our perpendicular bisector has a slope of m=-4 and a y-intercept of b=-6. Putting these in the slope-intercept form equation, we find the line to be ...

  y = mx +b

  y = -4x -6

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3 0
3 years ago
1) The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = 2x-3 and g(x) = 3x+8. Find f(x) multiplied by g(x). 2
Elena-2011 [213]

Answer:

1)6x^2+7x-24

2) x-4

3)  f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7

f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-15

4)f'(x)=(x-7)/3

Step-by-step explanation:

1) f(x)=2x-3 g(x)=3x+8

f(x)*g(x)=m(x)=(2x-3)(3x+8)=6x^2+16x-9x-24=6x^2+7x-24

2) f(x)=x^2+x-20 g(x)=x+5

f(x)/g(x)=p(x)=(x^2+x-20)/(x+5)=> by finding the roots of f(x) we obtain =

(x-4)(x+5)/(x+5)--->f(x)/g(x)=p(x)=(x-4)

3) f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7

f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-15

4) If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back x

y=3x+7

(y-7)/3=x=--> f'(x)=(x-7)/3

3 0
3 years ago
13. Add [-6-2 2] + [-3 2 1].<br> A. (-9-3-5]<br> B. [-3 0 3]<br> C. [-6 0 3]<br> D. [-9 0 3]
Tcecarenko [31]

Answer: The answer should be C if you were to add each point.

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