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BigorU [14]
3 years ago
13

6 loads of stone weigh 2/3 ton. Find the weight of 1 load of stone.

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0

\bf \begin{array}{ccll} loads&tons\\ \cline{1-2} 6&\frac{2}{3}\\\\ 1&x \end{array}\implies \cfrac{6}{1}=\cfrac{~~\frac{2}{3}~~}{x}\implies 6=\cfrac{~~\frac{2}{3}~~}{\frac{x}{1}}\implies 6=\cfrac{2}{3}\cdot \cfrac{1}{x} \\\\\\ 6=\cfrac{2}{3x}\implies 18x=2\implies x=\cfrac{2}{18}\implies x=\cfrac{1}{9}

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Please Help!!
barxatty [35]

Answer:

Ok, the speed is 18 mph.

The angle is 293°, and we usually measure the angles from the x-axis, so we can write our coordinates of velocity as:

Vx = 18mph*cos(293°) = 7mph.

Vy = 18mph*sin(293°) = -16.6mph.

Then we can write this as a vector (Vx, Vy)

Velocity = (7mph, -16.6mph)

Now, for the position, we can integrate over time, and using that the position (0,  0) is the starting point of the ship, we have that the position vector is:

P(t) = (7mph*t, -16,6mph*t)

Where t is the number of hours after the ship leaved the port.

If t = 0 is 0:00pm, then at 3:30pm we have t = 3 hours and 30 minutes

one hour has 60 minutes, then 30 minutes is equivalent to 0.5 hours.

Then 3:30pm we have t = 3.5 houes.

Now we replace this in the position vector and the location of the ship at 3:30pm is:

P(3.5h) = (7mph*3.5h, -16.6mph*3.5h) = (24.5 mi, -58.1 mi)

Where the first component describes the displacement in the x-axis, and the second component describes the displacement in the y-axis.

6 0
3 years ago
A rectangle measures 12 cm by 4 cm what is the area
Maslowich
In order to find the area you have to multiply length x width 
In this case our length and width are 12cm and 4cm 
So lets multiply those. :P
12 x 4 = 48 cm

Your area = 48cm²

Good Luck! :)
6 0
3 years ago
Roll two fair dice. Each die has six faces. A. Let A be the event that either a 3 or 4 is rolled first followed by an odd number
zhenek [66]

Answer:

A. 0.16

B. 0.58

C. No

D. Dependent

Step-by-step explanation:

A.

The sampling space has 36 outcomes.

The event A has 6 outcomes (3,1), (3,3), (3,5), (4,1), (4,3),(4,5)

So P(A)= 6/36 = 0.16

B.

The table in the picture shows the 15 outcomes that are not allowed, so there are 36-15 = 21 possible outcomes for B and its probability is 21/36 = 0.58

C.

Are A and B mutually exclusive events?

No since their intersection is not empty, for example (3,1) belongs to both A and B

D.

In order for A and B to be independent, it must happen that

P(A∩B)=P(A)P(B)

A∩B={(3,1),(3,3),(4,1)} so P(A∩B) = 3/36  

whereas

P(A)P(B) = (6/36)(21/36) = (1/6)(7/12)=7/72

So A and B are not independent.

7 0
3 years ago
9x+12x-21=27<br> How do I solve ?
alexandr402 [8]
You gotta combine like terms which would be 9x and 12x which gives you 21x .

6 0
3 years ago
Jessie bought f bags of potting soil for $2.00 each. Write an expression to show how much Jessie paid.
pav-90 [236]
I believe it is x = 2f

Happy studying
8 0
3 years ago
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