Answer this quick please
2 answers:
You might be interested in
Slope-intercept form: y = mx + b
[m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y) or the point where the line crosses through the y-axis]
To find the slope, you use the slope formula:
And plug in the two points
(-6, 2) = (x₁ , y₁)
(1, 16) = (x₂ , y₂)
[two negatives cancel each other out and become positive]
m = 2 Now that you found m, plug it into the equation
y = mx + b
y = 2x + b To find b, plug in one of the points into the equation
(-6, 2)
y = 2x + b
2 = 2(-6) + b
2 = -12 + b Add 12 on both sides
14 = b
(1, 16)
y = 2x + b
16 = 2(1) + b Subtract 2 on both sides
14 = b
Now that you found b, plug it into the equation
y = 2x + 14