I’m not 100% sure but I think it’s y=5x+20
Answer:
45.1feet
Step-by-step explanation:
Given the following
∠I=90°
∠G=62°, and
GH = 96 feet = Hypotenuse
Required
IG = Adjacent side
Using the SOH CAH TOA identity
Cos theta = Adj/hyp
Cos 62 =IG/96
IG = 96cos62
IG = 96(0.4695)
IG = 45.1feet
Hence the length of IG to the nearest tenth is 45.1feet
Answer:
look up desmos graphing calculator! you're welcome x
Step-by-step explanation:
i guess just times them all then divide up by how many numbers you have
The answer would be A because each x only has one y. Hope that makes sense!
