Given Information:
Total cards = 108
Red cards = 25
yellow cards = 25
Blue cards = 25
Green cards = 25
Wild cards = 8
Required Information:
Probability that a hand will contain exactly two wild cards in a seven-hand game = ?
Answer:
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
Step-by-step explanation:
The required probability is given by
P = number of ways of interest/total number of ways
The total number of ways of dealing a seven-card hand is
₁₀₈C₇
We want to select exactly 2 wild cards and the total wild cards are 8 so the number of ways of this selection is
₈C₂
Since the game is seven-card hand, we have to get the number of ways to select remaining 5 cards out of (108 - 8 = 100) cards.
₁₀₀C₅
Therefore, the setup for this problem becomes
P = number of ways of interest/total number of ways
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
This is the required setup that we can type into our calculators to get the probability of exactly two wild cards in a seven-hand card game with 8 wild cards and 108 total cards.
Answer:
The answer to your question is F = 78.8
Step-by-step explanation:
Equation
Multiply both sides by 9
Simplify
Divide both sides by 5
Simplify
Add 32 in both sides
Simplify (Inverse)
Substitute to find F
Simplify
F = 46.8 + 32
Result
F = 78.8
Answer:
314 large cups
Step-by-step explanation:
72x4.35=313.2
14/12 because if u go on calculator and do 5 divided by 12 + 9 divided by 12 u get 1.166667 or something and then u do 14/12 and it’s the same number.
