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Wittaler [7]
4 years ago
6

How do i solve this?

Mathematics
1 answer:
n200080 [17]4 years ago
5 0
The polynomial is not factorable, so use the quadratic formula.

y^2 + 8y + 19 = 0

x = (-b +- sqrt(b^2 - 4ac))/(2a)

x = (-8 +- sqrt(8^2 - 4(1)(19))/(2 * 1)

x = (-8 +- sqrt(64 - 76))/2

x = (-8 +- sqrt(-12))/2

If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.

If you have learned imaginary/complex numbers, then we'll continue.

x = (-8 +- 2i sqrt(3))/2

x = -4 +- i sqrt(3)
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Which of the following is a description of the data with a correlation coefficient of -0.3?
Klio2033 [76]
The magnitude of this number is far from 1, so it's low correlation

Since it's negative, so it's low negative correlation
8 0
3 years ago
What are potential roots of p(x) = x4 + 22x2 – 16x – 12
kow [346]
Simplify <span>22\times 2<span>22×2</span></span> to <span>44<span>44</span></span>
<span><span>{x}^{4}+44-16x-12<span><span>x<span><span>​4</span><span>​​</span></span></span>+44−16x−12</span></span>Collect like terms
<span><span>{x}^{4}+(44-12)-16x<span><span>x<span><span>​4</span><span>​​</span></span></span>+(44−12)−16x</span></span> Simplify</span><span><span>{x}^{4}+32-16x<span><span>x<span><span>​4</span><span>​​</span></span></span>+32−16x</span></span><span>
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8 0
3 years ago
Read 2 more answers
How much money has to be invested at 5.9% interest compounded continuously to have $15,000 after 12 years?
scoray [572]

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

Step-by-step explanation:

The given is,

                Future value, F  = $15,000

                           Interest, i = 5.9%

              ( compounded continuously )

                            Period, t = 12 years

Step:1

           Formula to calculate the present with compounded continuously,

                                       F=Pe^{(i)(t)}...............(1)

           Substitute the values in equation (1) to find the P value,

                                  15000=Pe^{(0.059)(12)}          ( ∵ i = \frac{5.9}{100}=0.059 )

                                  15000=Pe^{0.708}

                                  15000=P(2.0299)             ( ∵ e^{o.708} =2.0299 )

            We change the P (Present value) into the left side,

                                        P=\frac{15000}{2.0299}

                                            =7389.427

                                            ≅ 7389.43

                                         P = $ 7389.43

Result:

           The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.  

                       

8 0
3 years ago
(22+x-7)=(x-5)how do u do long division <br>​
photoshop1234 [79]

Answer:

there is no solution to this problem?

Step-by-step explanation:

wdym?

3 0
3 years ago
Read 2 more answers
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