Question

How do i solve this?

Answer 1

The polynomial is not factorable, so use the quadratic formula.

y^2 + 8y + 19 = 0

x = (-b +- sqrt(b^2 - 4ac))/(2a)

x = (-8 +- sqrt(8^2 - 4(1)(19))/(2 * 1)

x = (-8 +- sqrt(64 - 76))/2

x = (-8 +- sqrt(-12))/2

If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.

If you have learned imaginary/complex numbers, then we'll continue.

x = (-8 +- 2i sqrt(3))/2

x = -4 +- i sqrt(3)