Demand
D(q)=(12-q)^(1/2)
Revenue,
R(q)=q*D(q)=q*sqrt(12-q)
At maximum revenue,
R'(q)=0
where
R'(q)=sqrt(12-q)-q/[2(sqrt(12-q))]=0
Solve for q=8.
Hence, quantity=8, price=sqrt(12-q)=sqrt(12-8)=sqrt(4)=2
In numerical order (from least to greatest) : { 11,12,13,14,15,16,18}
Answer:
I think around 17 min...
Step-by-step explanation:
there is 60 sec in a minute so divide 60/8 , divide 60/6, then add them together....
60/8= 7.5 and 60/ 6=10
so 7.5+10 = 17.5
somewhere around there
Answer:
560,000L
Step-by-step explanation:
Given data
L=14m
W=8m
H=5m
Volume= L*W*H
Volume= 14*8*5
Volume= 560 m^3
1m^3 = 1000L
560m^3 = x
cross multiply
x= 560*1000
x= 560,000L
Hence the volume is 560,000L
7 pounds = 16 pounds and 1 pound = 6 pounds and 16 ounces.
(6 pounds + 16 ounces) minus (5 pounds + 10 ounces) = 1 pound + 6 ounces
