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Stolb23 [73]
3 years ago
15

2. Beta Particles

Chemistry
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

Explanation:

a. What is the mass number of the particle emitted from the nucleus during beta minus (β–) decay?

zero

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

⁴₆C → ¹⁴₇N + ⁰₋₁e

b. What kind of charge does the particle emitted from the nucleus during beta minus (β–) decay have?

Negative charge

Electron is emitted during beta decay and it carry negative charge.

c. What is another name for a beta minus (β–) particle?

Electron

During beta minus decay electron is emitted and neutron is converted into proton.

d. Write the balanced equation for the alpha decay that is below the “Show Equation.” Label the parent, daughter, and beta particle.

Equation is missing

a. What happens in the nucleus of an atom when an alpha particle is emitted?

When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4  and atomic number less than 2 as compared to the starting atom.

b. b. What happens in the nucleus of an atom when a beta particle is emitted?

When nucleus emit the beta particle neutron is converted into proton and this proton stay into the nucleus while at the same time electron is emitted. Thus atomic number is increased by one.

⁴₆C → ¹⁴₇N + ⁰₋₁e

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1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
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Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

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Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

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Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

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Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

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