A student carried out a simple distillation on a compound known to boil at 124 oc and they reported a boiling point of 116-117 o
analysis of the compound showed it was pure and calibration of the thermometer indicated that it was accurate. What procedural error might the student have made in setting up the distillation?
1 answer:
Answer :
The correct answer is due to incorrect position of thermometer .
Distillation is process of separating two volatile liquids on the basis of their boiling points .In involves the following set up ( shown in image )
Since the Boiling point is found is 116-117 C which is near to 124 C , also the purity was checked and thermometer was calibrated .
So the only error could be possible is position of thermometer .
The position of bulb of thermometer is very important to get an accurate reading of boiling point .The vapor so formed should touch the side walls of bulb as soon as they are formed .
May be the bulb of thermometer was kept far from the vapors formed by liquid so, s<u>ome of the vapor before reaching to bulb start condensing and their Temperature decreases </u>.
Hence , the temperature shown by thermometer was decrease than actual boiling point due to incorrect position of thermometer.
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Answer:
Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal
Explanation:
The molecular formula of mannoheptulose is C₇H₁₄O₇.
The structure is as shown in the attachment below.
Number of C-C bonds present in mannoheptulose = 6
Number of C-H bonds present in mannoheptulose = 8
Since the each C-C bond contains 76 Kcal of energy,
Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal
Also, since each C-H bond contains 91 Kcal of energy;
amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal
Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal
Answer:
21.5 g.
Explanation:
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In this case, since the reaction between the given compounds is:
We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:
Now, the moles of Li3P consumed by 15 g of Al2O3:
Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:
Therefore, the total mass of products is:
Which is not the same to the reactants (53 g) because there is an excess of Li₃P.
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