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UNO [17]
3 years ago
5

What mass of magnesium would combine with exactly 16.0 grams of oxygen

Chemistry
1 answer:
TEA [102]3 years ago
3 0
1.65g MgO = 1g Mg
1.65 - 1 = 0.65 g of O in MgO

solve it using proportion:
1g Mg / 0.65g O = x (g) Mg / 16g O
or 1 / 0.65 = x / 16

24.6 g is the answer.

if 1 gram of oxygen requires 1.65 grams of Mg
then 16 grams of oxygen will require 16 ( 1.65) or 26.4 grams.
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What is the mass of kilogram of an object that wileight 50.0 in round your answer to the nearest tenth
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3 years ago
Sugar is easily soluble in water and has a molar mass of 342.30 g/mol. What is the molar concentration of a 259.8 mL aqueous sol
DanielleElmas [232]

Answer:

M=0.822M

Explanation:

Hello,

In this case, given the mathematical definition of molar concentration as the moles of solute divided by the liters of solution:

M=\frac{n}{V}

We can easily compute it by firstly computing the moles of sugar by using its molar mass:

n=73.1g*\frac{1mol}{342.30g} =0.214mol

After that, we compute the concentration by realizing 259.8 mL equals 0.2598 L:

M=\frac{0.214mol}{0.2598L}\\ \\M=0.822mol/L

Or just:

M=0.822M

Considering molar units as mol/L

Best regards.

5 0
3 years ago
What is the silver ion concentration in a solution prepared by mixing 425 mL 0.397 M silver nitrate with 427 mL 0.459 M sodium p
Lisa [10]

Answer:

0 M is the silver ion concentration in a solution prepared mixing both the solutions.

Explanation:

molarity=\frac{\text{Moles of solute}}{\text{Volume of solution (L)}}

Moles of silver nitrate = n

Volume of the solution = 425 mL = 0.425  L (1 mL = 0.001 L)

Molarity of the silver nitrate solution = 0.397 M

n=0.397 M\times 0.425 L=0.1687 mol

Moles of sodium phosphate = n'

Volume of the sodium phosphate solution = 427 mL = 0.427  L (1 mL = 0.001 L)

Molarity of the sodium phosphate solution = 0.459 M

n'=0.459 M\times 0.427 L=0.1960 mol

3AgNO_3+Na_3PO_4\rightarrow Ag_3PO_4+3NaNO_3

According to reaction, 3 moles of silver nitrate reacts with 1 mole of sodium phosphate, then 0.1687 moles of silver nitrate will recat with :

\frac{1}{3}\times 0.1687 mol=0.05623 mol of sodium phosphate

This means that only 0.05623 moles of sodium phosphate will react with all the 0.1687 moles of silver nitrate , making silver nitrate limiting reagent and sodium phosphate as an excessive reagent.

So, zero moles of silver nitrate will be left in the solution after mixing of the both solutions and hence zero moles of silver ions will left in the resulting solution.

0 M is the silver ion concentration in a solution prepared mixing both the solutions.

4 0
3 years ago
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