All categories

3 years ago

What mass of magnesium would combine with exactly 16.0 grams of oxygen

1 answer:

3 0

1.65g MgO = 1g Mg
1.65 - 1 = 0.65 g of O in MgO

solve it using proportion:
1g Mg / 0.65g O = x (g) Mg / 16g O
or 1 / 0.65 = x / 16

24.6 g is the answer.

if 1 gram of oxygen requires 1.65 grams of Mg
then 16 grams of oxygen will require 16 ( 1.65) or 26.4 grams.

You might be interested in

What is the answer please tell me

Nastasia [14]

Answer:

you need to include the bottom portion, not enough info

Explanation:

5 0

3 years ago

Some one help me please I'm stuck Show using two conversion factors how you would convert from 0.020 kg into mg.

julia-pushkina [17]

Answer:

$=2.0x10^4mg$

Explanation:

Hello there!

In this case, when performing units conversions involving two proportional factors we need to make sure we first convert to the base unit and then to the target one; thus, since 1 kg = 1000 g and 1 g = 1000 mg, we set up the following expression:

$=0.020kg*\frac{1000g}{1kg} *\frac{1000mg}{1g} \\\\=2.0x10^4mg$

Best regards!

4 0

3 years ago

In the important industrial process for producing ammonia (the Haber Process), the overall reaction is:

Kisachek [45]

Answer:

Explanation:

Here we have to use stoichiometry.

First of all, we have to calculate the mass of 100% of yield:

1.7 g ------- 98%

X -------- 100%

X = 1.73 g (approximately)

Second, we have to calculate the mass of N2 that is necessary to react to produce the mass of 1.73g of NH3. To do that, we have to use the Molar mass of N2 and NH3 and don't forget the stoichiometric relationship between them.

Molar Mass N2 : 14x2 = 28 g/mol

Molar Mass NH3: 14 + 3 = 17 g/mol

28g (N2) ------- 17x2 (NH3)

X ------------ 1.73 g

X = 1.42 g (approximately)

5 0

3 years ago

Fe2O3(s)+3C(s)→2Fe(s)+3CO(g) how many grams of CO are produced when 32.0 grams of C react

krok68 [10]

Answer:

74.6 g

Explanation:

The computation of the number of grams produced at the time when 32.0 grams of C react is shown below:

As we know that

But before that we need to find out the moles of c i.e carbon which is

$= \frac{Grams }{C\ molar\ mass}$

$= \frac{32\ grams}{12.0107 g/mol}$

= 2.66 mol

As we know that

1 mol of C produces 1 mol of CO

So, for 2.66 mol, the mass of CO is

$= 2.66 \times28.0101 g/mol$

= 74.6 g

Basically we applied the above equation so that we can reach to the answer

8 0

3 years ago

Calculate the number of molecules and atoms present in 124 g of phosphorus

Brums [2.3K]

6.022*10^23 molecules
4*6.022*10^23 atoms = 24.08*10^23 atoms

3 0

3 years ago