The wavelength of the light is 6.00 × 10^(-5) m.
The formula connecting frequency <em>f</em> and wavelength λ is
<em>f</em>λ = <em>c</em>
where <em>c</em> = the speed of light [2.998 × 10^8 m·s^(-1)]
We can rearrange the formula to get
λ = <em>c</em>/<em>f
</em>
∴ λ = 2.998 × 10^10 m·s^(-1)/5.00 × 10^12 s^(-1) = 6.00 × 10^(-5) m = 60.0 µm
Answer:
Yes
2Ag + Cu(No3)2 -----(heat) ----- Cu + 2Agno3
When heat energy is passed through Cu(No3)2 then the reverse reaction will occur
Answer:
the first and last
Explanation:
the enthalpy Change is positive.
please like and Mark as brainliest
Chemical test to distinguish between propane and propene. (i) Bromine water test : Propane contains double bond, therefore when we pour the bromine water to propene sample, it decolouries the bromine water whereas propane which is a saturated hydrocarbon does not decolourise the bromine water.
Answer:
E = 1.5 x 10⁻¹⁷ J
Explanation:
The Rydberg equation for electronic transitions in the hydrogen atom is
1//λ = Rh x ( 1/n₁² - 1/n₂²)
where
Rh : Rydberg´s constant 1.09737 x 10 ⁷ m⁻¹
n₁ : Intial energy Level
n₂ : Final energy Level
But for non-hydrogen one electron ions such as He+ and Li2+ ²⁺ , the equation is similar but multiplied by Z²:
1/ λ = Rh Z² x ( 1/n₁² - 1/n₂²)
I will work this problem by fist calculating 1/λ and then use the equation E= hc/λ where
h : Planck´s constant 6.626 x 10 ⁻³⁴ J s
c : Speed of light 3 x 10 ⁸
1/ λ = 1.09737 x 10 ⁷ m⁻¹ ( 3² ) x ( 1/1² - 1/2² )
1/ λ = 7.4 x 10⁷ m⁻¹
E = 6.626 x 10 ⁻³⁴ J s x 3 x 10^8 m/s x 7.4 x 10⁷ m⁻¹
E = 1.5 x 10⁻¹⁷ J
