Answer:
you need to include the bottom portion, not enough info
Explanation:
Answer:

Explanation:
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In this case, when performing units conversions involving two proportional factors we need to make sure we first convert to the base unit and then to the target one; thus, since 1 kg = 1000 g and 1 g = 1000 mg, we set up the following expression:

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Answer:
Explanation:
Here we have to use stoichiometry.
First of all, we have to calculate the mass of 100% of yield:
1.7 g ------- 98%
X -------- 100%
X = 1.73 g (approximately)
Second, we have to calculate the mass of N2 that is necessary to react to produce the mass of 1.73g of NH3. To do that, we have to use the Molar mass of N2 and NH3 and don't forget the stoichiometric relationship between them.
Molar Mass N2 : 14x2 = 28 g/mol
Molar Mass NH3: 14 + 3 = 17 g/mol
28g (N2) ------- 17x2 (NH3)
X ------------ 1.73 g
X = 1.42 g (approximately)
Answer:
74.6 g
Explanation:
The computation of the number of grams produced at the time when 32.0 grams of C react is shown below:
As we know that
But before that we need to find out the moles of c i.e carbon which is


= 2.66 mol
As we know that
1 mol of C produces 1 mol of CO
So, for 2.66 mol, the mass of CO is

= 74.6 g
Basically we applied the above equation so that we can reach to the answer
6.022*10^23 molecules
4*6.022*10^23 atoms = 24.08*10^23 atoms