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3 years ago

During a phase change, such as melting or boiling, the kinetic energy __. Highlight correct answer

Chemistry

1 answer:

Pepsi [2]3 years ago

4 0

Answer: During a phase change, such as melting or boiling, the kinetic energy increases.

Explanation:

Kinetic energy is the energy obtained by the molecules of a substance due to their motion.

When phase change such as melting or boiling takes place then it means heat is absorbed by the substance. As a result, their molecules more even more rapidly from one place to another due to which more number of collisions take place.

Hence, a change in phase of substance occurs as kinetic energy increases in melting or boiling process.

Thus, we can conclude that during a phase change, such as melting or boiling, the kinetic energy increases.

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DNA, which is found in chromosomes in the nucleus

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Which substance is an electrolyte? 1. O2 2. Xe 3. C3H8 4. KNO3

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KNO3 is an electrolyte

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3 years ago

What is the most active non metallic element in group 16

Umnica [9.8K]

Metals=Reactivity increases as we move through the elements in the period table from top to bottom, and left to right. Nonmetals=Reactivity increases as we move through the elements in the periodic table, as we move from bottom to the top, and right to left. Since reactivity of nonmetals increases going up the periodic table, oxygen is therefore the most reactive nonmetal in the group. So, the answer is oxygen

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3 years ago

When sugar is burned, water vapor and carbon dioxide are produced.

Bas_tet [7]

Answer;

12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.

Explanation:

Using a balanced chemical equation we can identify the number of carbon, hydrogen, and oxygen atoms in sugar.

CxHyOn + 12O₂ → 11 H₂O + 12CO₂

When an equation is completely balanced, then the number of each atom of an element is equal on the reactant side and the product side.

Therefore;

For carbon; x = 12

For Hydrogen; y = (11×2) = 22

For Oxygen; n + (12×2) = 11 + (12×2)

= n + 24 = 11 + 24

n = 11

Therefore the sugar has, 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.

Thus the balanced equation would be;

C₁₂H₂₂O₁₁ + 12O₂ → 11 H₂O + 12CO₂

6 0

3 years ago

Read 2 more answers

A water treatment plant has 4 settling tanks that operate in parallel (the flow gets split into 4 equal flow streams), and each

ale4655 [162]

Answer:

a) When the 4 tanks operate in parallel the retention time is 1.26 hours.

b) If the tanks are in series, the retention time would be 0.31 hours

Explanation:

The plant has 4 tanks, each tank has a volume V = 600 $m_3$ . The total flow to the plant is Ft = 12 MGD (Millions of gallons per day)

When we use the tanks in parallel, it means that the total flow will be divided in the total number of tanks. F1 will be the flow of each tank.

Firstly, we should convert the MGD to $m_3 /day$ . In that sense, we can calculate the retention time using the tank volume in $m_3$ .

$Ft =12 \frac{MG}{day} (\frac{1*10^6 gall}{1MG} ) (\frac{3.78 L}{1 gall} ) (\frac{1 dm^3}{1L} ) (\frac{1 m^3}{10^3 dm^3} ) = 45360 \frac{m^3}{day}$

After that, we should divide the total flow by four, because we have four tanks.

$F1 = Ft/4 =(45360 \frac{m^3}{d} )/4 = 11 340 \frac{m^3}{d}$

To calculate the retention time we divide the total volume V by the flow of each tank F1.

$t1 =\frac{V1}{F1} = \frac{600 m^3}{11340 \frac{m^3}{d} } = 0.0529 day\\t1 = 0.0529 d (\frac{24 h}{1d} ) = 1.26 h$

After converting t1 to hours we found that the retention time when the four reactors are in parallel is 1.26 hours.

If the four reactors were working in series, the entire flow goes first through one tank, then the second and so on. It means the total flow will be the flow of each tank.

In that order of ideas, the flow for reactors in series will be F2, and will have the same value of F0.

F2 = F0

To calculate the retention time t2 we divide the total volume V by the flow of each tank F2.

$t2 =\frac{V1}{F2} = \frac{600 m^3}{45360 \frac{m^3}{d} } = 0.01 day\\t2 = 0.01 d (\frac{24 h}{1d} ) = 0.31 h$

After converting t2 to hours we found that the retention time when the four reactors are in series is 0.31 hours.

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3 years ago