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Lelu [443]
3 years ago
11

After ingestion of a food particle, pH changes and enzymes contributed by the ________ will digest and hydrolyze the ingested pa

rticle in the phagocytic vacuole.
Biology
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

as the question is incomplete i have added the link to full question in ask for detail section.

b) Lysosome

Explanation:

After ingestion of a food particle, pH changes and enzymes contributed by the __Lysosome__ will digest and hydrolyze the ingested particle in the phagocytic vacuole.

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Helicase

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The DNA double helix is unzipped by the enzyme *HELICASE*. The enzyme breaks the hydrogen bond between the bases thereby causing the strands of the double helicase to unzip. The action of the helicase enzyme uses energy from ATP. The unzipping of the double helix does not occur in a swift move. One end of the DNA molecule with 5'-3' is opened up showing the antiparallel single strands. The end that is opened is termed INITIATION SITE of replication. The opening look like someone standing with legs wide open. The wide opening is called REPLICATION FORK. The single strands of the fork are usually unstable but their stability is maintained by the DNA-binding-proteins. Having opened the double helix, the replication would then continue in the 5'-3' direction of one of the two antiparallel single strands.

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Each of the four pedigrees that follow represents a human family within which a genetic disease is segregating. Affected individ
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 Answer:

<u> The following four traits are -: </u>

  • <u>Pedigree 1 -</u> A recessive trait (autosomal recessive)  is expressed by pedigree 1.
  • <u>Pedigree 2- Recessive inheritance is defined by Pedigree 2. </u>
  • <u>Pedigree 3</u> - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
  • <u>Pedigree 4-</u> An X-like dominant trait is expressed by Pedigree 4.    

Explanation:

<u>Explaination of each pedigree chart</u>-

  • Pedigree 1 demonstrates the <u>recessive trait </u>since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected. X^A In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa)
  • <u> Recessive inheritance</u> is defined by <u>Pedigree 2</u>. This is<u> X-related inheritance as autosomal recessive</u> inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical  Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes (X^A) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical X^A must be contributed by II-6.
  • The inheritance of the<u> dominant trait</u> is demonstrated by <u>Pedigree 3 </u>because affected children still have affected parents (remember that all four diseases are rare). The trait must be <u>autosomal dominant</u> because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
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In the question the pedigree chart was missing ,hence it is given below.

     

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