All categories

3 years ago

Why does a piece of iron in a current-carrying loop increase the magnetic field strength?

Physics

1 answer:

Agata [3.3K]3 years ago

7 0

Answer: The magnetic domain in the metal is aligned when a piece of metal is placed in a magnetic coil.

Explanation: When a piece of metal is placed in a magnetic coil the field causes the electrons of the metal to gain some magnetic properties , the magnetic field causes the electrons of the metal to align and move in a similar direction forming domains, this action of the electrons of the metal also add to the magnetic properties of the coil, therefore increasing it.

You might be interested in

A projectile is launched from ground level to the top of a cliff which is 195 m away and 155 m high. If the projectile lands on

muminat

Answer:

66.02m/s

Explanation:

the equation describing the distance covered in the horizontal direction is

$x=ucos\alpha t-(1/2)gt^{2}$ but the acceleration in the horizontal path is zero, hence we have

$x=ucos\alpha t$

Since the horizontal distance covered is 155m at 7.6secs, we have $ucos\alpha =\frac{155}{7.6} \\ucos\alpha =20.38.............equation 1$

Also from the vertical path, the distance covered is expressed as

$y=usin\alpha t-(1/2)gt^{2}$

since the horizontal distance covered in 7.6secs is 195m, then we have

$y=usin\alpha t-(1/2)gt^{2}\\y=7.6usin\alpha -4.9(7.6)^{2}\\478.02=7.6usin\alpha \\usin\alpha =62.9...........equation 2$

Hence if we divide both equation 1 and 2 we arrive at

$\frac{usin\alpha }{ucos\alpha } =\frac{62.9}{20.38} \\tan\alpha =3.08\\\alpha =tan^{-1}(3.08)\\\alpha =72.02^{0}\\$

Hence if we substitute the angle into the equation 1 we have

$ucos72.02=20.38\\u=66.02m/s$

Hence the initial velocity is 66.02m/s

3 0

4 years ago

An object experiences a 8.9 N force and accelerates 6 m/sec2. What is the object's

Inessa [10]

b stupidrwfs

planation:

3 0

3 years ago

URGENT!! ILL GIVE

eimsori [14]

Answer:

melting point (a)

Explanation:

7 0

2 years ago

¿Cuál será la potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 v

g100num [7]

Answer:

La potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 volt, si la corriente que circula por el circuito de la ampolleta es de 0.45 ampere, es 99 Watts.

Explanation:

Potencia es la velocidad o rapidez con la que se consume la energía. Siendo la energía la capacidad que tiene un mecanismo o dispositivo eléctrico cualquiera para realizar un trabajo, también se puede definir potencia como la energía desarrollada o consumida en una unidad de tiempo. Su unidad de medida es el Watt.

La ley de Watt establece que la potencia eléctrica P suministrada por un elemento de circuito, es directamente proporcional al producto entre la tensión de la alimentación V del circuito y la intensidad de corriente I que circula por él.

Matemáticamente, la ley de Watt se expresa:

P = V.I

donde V es medida en Volt e I es medida en Ampere.

En este caso:

V=220 volt
I= 0.45 ampere

Reemplazando:

P= 220 volt* 0.45 ampere

P= 99 Watts

<u><em>La potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 volt, si la corriente que circula por el circuito de la ampolleta es de 0.45 ampere, es 99 Watts.</em></u>

3 0

3 years ago

Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml

Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$