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2 years ago

Which best explains how Selena can correct her error?

Physics

2 answers:

alekssr [168]2 years ago

8 0

Answer:

B:She can change the arrows so they show current traveling in opposite directions on the sides of the loop.

Explanation:

Scilla [17]2 years ago

7 0

Answer: well first you have to show or tell us the “error“ Selena made

Explanation:

You might be interested in

What’s the answer?? middle question

juin [17]

The new volume = 3 x 52.6 that’s because as the pressure decreases by 1/3 the volume increases x3

6 0

2 years ago

A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0 m high cliff. At the instant the ball i

scoray [572]

Answer:

The distance traveled by the woman is 34.1m

Explanation:

Given

The initial height of the cliff

yo = 45m final, positition y = 0m bottom of the cliff

y = yo + ut -1/2gt²

u = 20.0m/s initial speed

g = 9.80m/s²

0 = 45.0 + 20×t –1/2×9.8×t²

0 = 45 +20t –4.9t²

Solving quadratically or by using a calculator,

t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s

So this is the total time it takes for the ball to reach the ground from the height it was thrown.

The distance traveled by the woman is

s = vt

Given the speed of the woman v = 6.00m/s

Therefore

s = 6.00×5.69 = 34.14m

Approximately 34.1m to 3 significant figures.

3 0

2 years ago

Which countries have high productivity, but are not among the top 10 for human development? Check all that apply.

trasher [3.6K]

Answer:

Belgium

France

Luxembourg

Explanation:

These are the ones that are in the High Productivity chart, but not in the HDI chart

8 0

2 years ago

On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max

sesenic [268]

Work done by a given force is given by

$W = F.d$

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = $W_1 = Fdcos\theta$

$W_1 = 12*5cos15$

$W_1 = 57.96 J$

Now similarly work done by frictional force

$W_2 = Fdcos\theta$

$W_2 = 4*5cos180$

$W_2= -20 J$

Now total work done on sled

$W_{net}= W_1 + W2$

$W_{net} = 57.96 - 20 = 37.96 J$

7 0

2 years ago

The weight of a luggage is 69.3 N on the moon. Find its weight on the Earth.

Galina-37 [17]

Answer:

Explanation:

weight on moon = 1/6* weight on earth

69.3=1/6*weight on earth

weight on earth = 69.3*6

weight on earth = 415.8 N

8 0

2 years ago