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3 years ago

I feel death among us

Physics

2 answers:

DanielleElmas [232]3 years ago

6 0

Answer:

same....

Explanation:

Wanna be friends?

liberstina [14]3 years ago

3 0

same but who knows how 2021 might go

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Question 15 plz picture above

Pie

15) C. The amount of each element that begins....

8 0

3 years ago

Match the type of radiation to a correct description of it. A. Alpha The radiation particle is negatively charged. B. Beta The r

lawyer [7]

Alpha - <span>The radiation particle is positively charged.
</span>Beta - <span>The radiation particle is negatively charged.
</span>Gamma - The radiation is a wave, not a particle.

5 0

3 years ago

A star with an original mass of 8 to 25 solar masses will ultimately become a ?

BaLLatris [955]

The answer is C. Neutron star.

8 0

3 years ago

Measurements made on an operating centrifugal pump indicate that for a flow rate of 240 gpm, 6 HP are being consumed. The operat

Ludmilka [50]

Answer:

62.1 ft

Explanation:

We know that $1 gpm= 0.0022 ft^{3}/s$ hence 240 gpm will be

$240*0.0022=0.528 ft^{3}/s$

From the formula of obtaining efficiency

$\eta=\frac {\gamma Q h_a}{500W_{in}}$ and making $h_a$ the subject we have

$h_a=\frac {\eta*550*W_{in}}{\gamma Q}$ where Q is flow rate, $\gamma$ is specific weight of water, $h_a$ is actual head rise and $W_{in}$ is the power input to the compressor

Substituting 0.62 for $\eta$ , 6hp for $W_{in}$ , $62.4 lb/ft^{3}$ for $\gamma$ and $0.528 ft^{3}/s$ for Q then

$h_a=\frac {0.62*550*6}{62.4*0.528}=\frac {2046}{32.9472}=62.09936\approx 62.1 ft$

Therefore, actual head rise of the water being pumped is 62.1 ft

6 0

3 years ago

A DC current of 60 mA can cause paralysis of the body's respiratory muscles and hence interfere with breathing, but only 15 mA (

Liula [17]

To solve this problem it is necessary to apply the concepts related to Ohm's Law to find the voltage in the case of direct current. While for the Alternate current we use the concept of RMS voltage.

PART A) In the case of DC we have to,

V=IR

Where,

I = Current

R = Resistance

Where the current is 60mA y the resistance is $1000\Omega$ , then the potential would be