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Sedaia [141]
3 years ago
15

a light ray traveling in air enters a second medium and its speed slows to 1.71 × 10^8 meters per second. what is the absolute i

ndex of refraction of the second medium? (1) 1.00 (3) 1.75 (2) 0.570 (4) 1.94
Physics
2 answers:
givi [52]3 years ago
8 0
The absolute refractive index is equal to the speed of light of the wave in air divided by the speed of light in the second medium. This means that it is equal to 3 x10^8 / 1.71 x10^8. This means the answer is 1.75
Dmitriy789 [7]3 years ago
8 0
Absolute Index of Refraction 

                                               =  Velocity of Light in air / Velocity of light in medium

                                               =   3 * 10⁸  m/s   / 1.71 * 10⁸ m/s

                                               = 1.75

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How would you change the distance between two charged particles to increase the electric force between them by a factor of 16
Naily [24]

The electrostatic force between two charges is inversely
proportional to the square of the distance between them.

So if you want to multiply the force by, say, ' Q ',
you need to multiply the distance by  ( 1 / √Q ) .

We want to multiply the force by 16, so we need to
multiply the distance by    ( 1 / √16 )  =  ( 1 / 4 ) .

The distance should be changed to  1/4  of what it is now.

4 0
3 years ago
Read 2 more answers
Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
4vir4ik [10]

The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance D_{A} beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed v_{A}. Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed v_{B}, which is greater than v_{A}.

Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.

Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

Answer: Part A: t=\frac{D_{A}}{v_{B}-v_{A}}

              Part B: x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Explanation: First, let's write an equation of motion for each car.

Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:

x=x_{0}+vt

where

x_{0} is initial position

v is velocity

t is time

Car A started the race at a distance. So at t = 0, initial position is D_{A}.

The equation will be:

x_{A}=D_{A}+v_{A}t

Car B started at the starting line. So, its equation is

x_{B}=v_{B}t

Part A: When they meet, both car are at "the same position":

D_{A}+v_{A}t=v_{B}t

v_{B}t-v_{A}t=D_{A}

t(v_{B}-v_{A})=D_{A}

t=\frac{D_{A}}{v_{B}-v_{A}}

Car B meet with Car A after t=\frac{D_{A}}{v_{B}-v_{A}} units of time.

Part B: With the meeting time, we can determine the position they will be:

x_{B}=v_{B}(\frac{D_{A}}{v_{B}-v_{A}} )

x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Since Car B started at the starting line, the distance Car B will be when it passes Car A is x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}} units of distance.

5 0
3 years ago
The rebirth of science and learning during the fifteenth century is termed the
Pepsi [2]
The Renaissance, was the rebirth to science as well as many other advancements
5 0
4 years ago
iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weig
Alika [10]

Answer:

453 gm

Explanation:

<u>Immersed </u>objects are buoyed up by force equal to mass of displaced liquid

400 + 53 = 453 gm  in air

8 0
2 years ago
Find the angle of depression from the top of a lighthouse 250 feet above water level to the water line of a ship 2.5 miles offsh
Rudik [331]
Height of the lighthouse = 250 feet
Distance of the ship from the shore = 2.5 miles
We already know that
1 mile = 5280 feet
Then
2.5 miles = 5280 * 2.5
               = 13200 feet
Now, to find the angle of depression, we can use the formula
<span>θ = <span>tan<span>−1 </span></span>(13200/250)
</span>   = 1.50 degrees
I hope that this is the answer that you were looking for and the answer has come to your desired help. 
4 0
4 years ago
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