Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem
t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).
So t = √(3r^2) = √3r answer.
Question a: 3cm
question b: 8cm
question c: 12cm
(could be wrong)
The wording of your question suggests that there were answer choices. Mind sharing them?
The system <span>y=-2x^2 y=x-2 would be best written as:
</span><span>y=-2x^2
y=x-2 If you subst. x-2 for y in the first equation, you'll get:
x-2 = -2x^2, or 2x^2 + x - 2 = 0.
</span>
Answer:
The area of the region between the graph of the given function and the x-axis = 25,351 units²
Step-by-step explanation:
Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15
If 'f' is a continuous on [a ,b] then the function

By using integration formula

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

<em>On integration , we get</em>
= 

= 
After simplification and cancellation we get
= 
on calculation , we get
= 
On L.C.M 15
= 
= 25 351.2 units²
<u><em>Conclusion</em></u>:-
<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>