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olganol [36]
3 years ago
7

Write a MATLAB statement that results in the input request shown in bold. The​ >> shows where your statement is​ typed, an

d the​ | shows where the cursor waits for input. The display must be correctly positioned. Each has a space before the cursor​ (shown as​ |). The input variable name and the variable type are shown at the right.
Engineering
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

For the given input request, the MATLAB statement is as follows

Bolt=input(‘Enter the length of the bolt in inches:’);

Consequently, the statement is written

The next MATLAB statement is

Bolt=input(‘Enter the company’s name: ‘s’);

The statement is therefore, written

Finally

Line_color=menu(‘Choose a color’, ‘Red’, ‘Green’, ‘Blue’);

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The evaporator:
iris [78.8K]

Answer:

Option B

Explanation:

An evaporator along with  cold low pressure refrigerant absorbs heat from the air within the passenger compartment thereby supplying cool air for the occupants.

Hence, option B is correct

6 0
3 years ago
A hypothetical metal alloy has a grain diameter of 1.7 102 mm. After a heat treatment at 450C for 250 min, the grain diameter ha
Romashka-Z-Leto [24]

Answer:

the required time for the specimen is  1109.4 min

Explanation:

Given that;

diameter of metal alloy d₀ = 1.7 × 10² mm

Temperature of heat treatment T = 450°C = 450 + 273 = 723 K

Time period of heat treatment t = 250 min

Increased grain diameter 4.5 × 10² mm

grain diameter exponent n = 2.1

First we calculate the time independent constant K

dⁿ - d₀ⁿ = Kt

K = (dⁿ - d₀ⁿ) / t

we substitute

K = (( 4.5 × 10² )²'¹ - ( 1.7 × 10² )²'¹) / 250

K = (373032.163378 - 48299.511117) / 250

K = 1298.9306 mm²/min

Now, we calculate the time required for the specimen to achieve the given grain diameter ( 8.7 × 10² mm )

dⁿ - d₀ⁿ = Kt

t = (dⁿ - d₀ⁿ) / K

t = (( 8.7 × 10² )²'¹ - ( 1.7 × 10² )²'¹) / 1298.9306

t = ( 1489328.26061158 - 48299.511117) / 1298.9306

t = 1441028.74949458 / 1298.9306

t = 1109.4 min

Therefore, the required time for the specimen is  1109.4 min

4 0
3 years ago
1 gallon of benzene having a density of 0.88 g/mL is spilled in 200 feet by 150 foot lake having an average depth of 6 feet. Wha
Irina18 [472]

Answer:

The concentration of benzene in this contaminated lake would be 653549ng/L.

Explanation:

The concentration C of a contaminant over a body of water of volume V can be obtained as:

C=Mass contaminant / V

In this case, the volume of the body of water:

V=200ft\cdot150ft\cdot6ft=5097.033m^3

The mass of the contaminant (Benzene):

m=\delta V_{ben}=0.88\frac{g}{ml} 1gal(us)=3.3311kg

Therefore:

C=\frac{m_{ben}}{V_{lake}}=6.53549\cdot10^{-4}kg/m^3=653549ng/l

4 0
4 years ago
The acceleration of a particle is given by a = 2t − 10, where a is in meters per second squared and t is in seconds. Determine t
tensa zangetsu [6.8K]

Answer

given,

a = 2 t - 10

velocity function

we know,

\dfrac{dv}{dt}=a

\dfrac{dv}{dt}=(2t-10)

integrating both side

\int dv =\int (2t -10) dt

 v = t² - 10 t + C

at t = 0   v = 3

so, 3 = 0 - 0 + C

     C = 3

Velocity function is equal to v = t² - 10 t + 3

Again we know,

\dfrac{dx}{dt}=v

\dfrac{dx}{dt}=(t^2-10t + 3)

integrating both side

\int dx =\int (t^2-10t + 3)dt

x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t + C

now, at t= 0 s = -4

-4 = \dfrac{0^3}{3}- 10\dfrac{0^2}{2} + 0 + C

C = -4

So,

x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4

Position function is equal to x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4

8 0
4 years ago
A gas turbine has a thermal efficiency of 20% and develops a power output of 8 MW. Determine the fuel consumption rate if heatin
AlexFokin [52]

Answer:

0.8 kilograms of fuel are consumed each second.

Explanation:

As turbines are steady-state devices, the thermal efficiency of a turbine is equal to the percentage of the ratio of the output power to fluid power, that is:

\eta_{th} = \frac{\dot W}{\dot E} \times 100\,\%

The fluid power is:

\dot E = \frac{\dot W}{\eta} \times 100\,\%

\dot E = \frac{8\,MW}{20\,\%}\times 100\,\%

\dot E = 40\,MW

Which means that gas turbine consumes 40 megajoules of fluid energy each second, which is heated and pressurized with help of the fuel, whose amount of consumption per second is:

50\,\frac{MJ}{kg} = \frac{40\,MJ}{m_{fuel}}

m_{fuel} = 0.8\,kg

0.8 kilograms of fuel are consumed each second.

3 0
3 years ago
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