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marin [14]
3 years ago
8

Technician A says that a defective crankshaft position sensor can cause a no spark condition technician B says that a faulty ign

ition control module can cause a no spark condition which technician is correct
Engineering
1 answer:
Aliun [14]3 years ago
5 0
Both tech distributor ignition
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Which one of these is not a successful budgeting strategy
Amiraneli [1.4K]

Answer:

I can't tell you that ANSWER because I need to see the answers they gave you to circle or something

6 0
3 years ago
Read 2 more answers
This is a new technology meant to reduce vehicle roll-overs A. Lane-departure warning B. Anti-lock brakes C. Inspection reports
Naily [24]

Answer:

(b) Anti-lock brakes

Explanation:

The short form of Anti-lock Braking System commonly known as ABS. Its working is based on the fact that the user will be in safe condition when he apply sudden brakes. It usually happens when a in vehicle moving with high speeds on highways encounter anything before them, they hit brakes suddenly which may lead to the tires loosing traction and contact with the roads and rolling over due to inertia as a result of the high speeds. These conditions result in very serious mishaps. Anti-lock system  aims to reduce the mishaps and losses which arise solely due to the locking of tires when brakes are applied. Anti-lock system significantly reduces speed and maintains a safer environment for the user and the vehicle.

5 0
3 years ago
The cold drawn AISI 1040 steel bar with 25-mm width and 10-mm thick has a 6- mm diameter thru hole in the center of the plate. T
4vir4ik [10]

Answer:

A)  ( N ) = 1.54

B)  N ( Goodman ) = 1.133,  N ( Morrow) = 1.35

Explanation:

width of steel bar = 25-mm

thickness of steel bar = 10-mm

diameter = 6-mm

load on plate = between 12 kN AND 28 kN

notch sensitivity = 0.83

A ) Fatigue factor of safety based on yielding criteria

= δa + δm = \frac{Syt}{n}   =  91.03 + 227.58 = 490 / N

therefore Fatigue number of safety ( N ) = 1.54

δa (amplitude stress ) = kf ( Fa/A) = 2.162 * ( 8*10^3 / 190 ) = 91.03 MPa

A = area of steel bar = 190 mm^2 , Fa = amplitude load = 8 KN , kf = 2.162

δm (mean stress ) = kf ( Fm/A ) = (2.162 * 20*10^3 )/ 190 = 227.58 MPa

Fm = mean load  = 20 *10^3

B) Fatigue factor of safety based on Goodman and Morrow criteria

δa / Se + δm / Sut = 1 / N

= 91.03 / 183.15 + 227.58 / 590 = 1 /N

Hence N = 1.133 ( based on Goodman criteria )

note : Se = endurance limit (calculated) = 183.15 , Sut = 590

applying Morrow criteria

N =   1 / ( δa/Se) + (δm/ δf )

   = 1 / ( 91.03 / 183.15 ) + (227.58 / 935 )  

   = 1.35

6 0
3 years ago
3 examples of technology transfer pls
OLEGan [10]

Answer: electrical, mathematical, and geographical

Explanation: Yee  

                              - Cash Nasty

3 0
3 years ago
Read 2 more answers
5. A typical paper clip weighs 0.59 g and consists of BCC iron. Calculate (a) the number of
marta [7]

Answer:

(a) 3.185*10^{21} cells

(b) 6.37*10^{21} atoms

Explanation:

(a)

Volume, V of unit cell

V=(2.866*10^{-8})^{3}=2.354*10^{-23}

Number of unit cells, N

N=\frac {W_{mat}}{V\rho_{mat}} Where W_{mat} is weight of material and \rho_{mat} is density of material

N=\frac{0.59}{7.87*(2.354*10^{-23}}=3.185*10^{21} cells

(b)

Number of atoms in paper clip

This is a product of number of unit cells and number of atoms per cell

Since iron has 2 atoms per cell

Number of atoms of iron=3.185*10^{21} cells*2 atoms/cell=6.37*10^{21} atoms

8 0
3 years ago
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