Answer:
v = 21.409 m/s
Explanation:
Given data:
Total weight of the platform and weight together, W = 900 N
Diameter of the water jet = 5 cm = 0.05 m
Now,
the force exerted by the water jet is balancing the platform
also,
Force exerted by the water jet = ρAv²
where,
ρ is the density of the water = 1000 kg/m³
A is the area of the outlet of the jet =
or
A = 0.00196 m²
v is the velocity of the jet
thus,
W = ρAv²
or
900 = 1000 × 0.00196 × v²
or
v = 21.409 m/s
Hence, the velocity of the jet is 21.409 m/s
Answer:
A) After 2.5 milliseconds
Explanation:
Given that :
In a CAN bus, there are three computers: Computer A, Computer B, and Computer C.
Length in time of the message sent are 2 milliseconds long
As the computer start sending the message; the message are being sent at a message duration rate of 2 milliseconds
250 microseconds later, Computer B starts to send a message; There is a delay of 250 microseconds = 0.25 milliseconds here at Computer B
and 250 microseconds after that, Computer C starts to send a message
Similarly; delay at Computer C = 0.25 milliseconds
Assuming is the retransmit time for Computer A to retransmit its message, Then :
=
= 2 milliseconds + 0.25 milliseconds + 0.25 milliseconds
= 2.5 milliseconds
Thus; the correct option is A) After 2.5 milliseconds
Answer:
Head loss = 28.03 m
Explanation:
According to Bernoulli's theorem for fluids we have
Applying this between the 2 given points we have
Here is the head loss that occurs
Since the pipe is horizantal we have
Applying contunity equation between the 2 sections we get
Since the cross sectional area of the both the sections is same thus the speed
is also same
Using this information in the above equation of head loss we obtain
Applying values we get
Answer: If saturation effects are ignored, the magnetization curve of Fig. 7.27 becomes a straight line with a constant slope of 150 volts per ampere of field current.
Explanation: